[英]Opening a modal in a function call instead of .click()
I have this jquery function that opens up a modal anytime a button is pressed of type 'btnClr' 我有这个jquery函数,可在每次按下“ btnClr”类型的按钮时打开模式
$(document).ready(function () {
$('#[id*=btnClr]').onload(function () {
$dialog.dialog('open');
});
var $dialog = $("#trUI").dialog({
autoOpen: false,
title: "Edit Configurations",
width: "auto",
buttons: {
"Submit": function (e) {
AddKeyValue();
$(this).dialog('close');
},
"Cancel": function (e) {
ClearKeyVal();
$(this).dialog('close');
}
}
});
});
I'm trying to move it into a function so that it's opened anytime the function is called instead of any time the button is clicked. 我试图将其移动到函数中,以便在调用函数时(而不是在单击按钮时)打开它。
I was able to achieve this with this code 我能够用这段代码实现
function modalOpen() {
var $dialog = $("#trUI")
.dialog({
title: "Edit Configurations",
width: "auto",
buttons: {
"Submit": function(e) {
AddKeyValue();
$(this).dialog('close');
},
"Cancel": function(e) {
ClearKeyVal();
$(this).dialog('close');
}
}
});
}
However, any one of the buttons will only work once. 但是,任何一个按钮只能使用一次。
Does anybody have any recommendations for how to do this? 有人对此有任何建议吗?
I believe your issue is that you also are not "opening" the dialog. 我相信您的问题是您也没有“打开”对话框。 Move $dialog.dialog('open');
移动$ dialog.dialog('open'); into the new function you wrote, so whenever it is called it will open it.
到您编写的新函数中,因此无论何时调用它都会将其打开。
I was able to get it working. 我能够使它工作。 It was a TINY change in code.
这是代码的微小变化。 All I had to change was the call to dialog("open")
我只需要更改对dialog(“ open”)的调用
// some function{
$("#trUI").dialog('open'); //instead of $dialog.dialog("open")
}
$(document).ready(function () {
$("#trUI").dialog({
autoOpen: false,
title: "Edit Configurations",
width: "auto",
buttons: {
"Submit": function (e) {
AddKeyValue();
$(this).dialog('close');
},
"Cancel": function (e) {
ClearKeyVal();
$(this).dialog('close');
}
}
});
});
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