在MySQL中过滤表，其中两个时间戳列之间存在差异

Question

I have a table in MySQL which includes the datetime columns open_time and close_time .

How can I select only rows in which close_time is at least one minute greater than open_time ?

Answer 1

WHERE TIMESTAMPDIFF(SECOND,close_time,open_time) > 60

更多信息： http : //www.w3resource.com/mysql/date-and-time-functions/mysql-timestampdiff-function.php

Answer 2

You could use TIMESTAMPDIFF(unit, datetime_expr1, datetime_expr2) and something like

select * from MyTab T where TIMESTAMPDIFF(MINUTE,open_date,close_date) > 1

From docs

TIMESTAMPDIFF(unit,datetime_expr1,datetime_expr2)

Returns datetime_expr2 − datetime_expr1, where datetime_expr1 and datetime_expr2 are date or datetime expressions. One expression may be a date and the other a datetime; a date value is treated as a datetime having the time part '00:00:00' where necessary. The unit for the result (an integer) is given by the unit argument. The legal values for unit are the same as those listed in the description of the TIMESTAMPADD() function.

mysql> SELECT TIMESTAMPDIFF(MONTH,'2003-02-01','2003-05-01'); -> 3
mysql> SELECT TIMESTAMPDIFF(YEAR,'2002-05-01','2001-01-01'); -> -1
mysql> SELECT TIMESTAMPDIFF(MINUTE,'2003-02-01','2003-05-01 12:05:55'); -> 128885

Note The order of the date or datetime arguments for this function is the opposite of that used with the TIMESTAMP() function when invoked with 2 arguments.