在Flask中运行python脚本
[英]running a python script within Flask
问题描述
So I have this simple python script running on Flask that I'd like to pass variables to with an ajax jQuery request. 
因此，我在Flask上运行了这个简单的python脚本，希望通过ajax jQuery请求将变量传递给该脚本。 I might be missing something obvious but I can't get it to work properly. 我可能会遗漏一些明显的东西，但是我无法使其正常工作。
@app.route('/test', methods=['GET', 'POST'])
def test():
my_int1 = request.args.get('a')
my_int2 = request.args.get('b')
my_list = [my_int1, my_int2]
with open('my_csv.csv', 'wb') as myfile:
wr = csv.writer(myfile, quoting=csv.QUOTE_ALL)
wr.writerow(my_list)
return '' #does one have to have an return even tho it is just a script?
So, above will work fine when just passing parameters to the URL field: http://127.0.0.1:5000/test?a=10&b=25 however, trying this in the chrome console will not yield any output at all: 因此，仅在将参数传递到URL字段时，上述方法就可以正常工作： http://127.0.0.1:5000/test?a=10&b=25 : http://127.0.0.1:5000/test?a=10&b=25 : http://127.0.0.1:5000/test?a=10&b=25但是，在chrome控制台中尝试此操作根本不会产生任何输出：
$.ajax({
method: "POST",
url: "127.0.0.1:5000/test",
data: {a: 10, b: 25},
dataType: "script"
});
What am I missing and why does the above jquery ajax request not work? 我缺少什么，为什么上面的jquery ajax请求不起作用？ $.ajax is not a function(…)
3 个解决方案
解决方案1
1 2016-09-02 18:04:12
Please refer to http://flask.pocoo.org/docs/0.11/api/#flask.Request 请参考http://flask.pocoo.org/docs/0.11/api/#flask.Request
request.args : If you want the parameters in the URL
request.form : If you want the information in the body (as sent by a html POST form)
request.values : If you want both
Try this 尝试这个
@app.route('/test', methods=['GET', 'POST'])
def test():
my_int1 = request.values.get('a')
my_int2 = request.values.get('b')
解决方案2
1 已采纳 2016-09-02 20:51:16
Please, try with the following code and let me know if that's what you are looking for: 请尝试以下代码，让我知道您是否正在寻找它：
from flask import Flask, request
import csv
app = Flask(__name__)
@app.route('/test', methods=['GET', 'POST'])
def test():
if request.is_xhr:
a = request.json['a']
b = request.json['b']
else:
a = request.args.get('a')
b = request.args.get('b')
my_list = [a, b]
with open('my_csv.csv', 'wb') as myfile:
wr = csv.writer(myfile, quoting=csv.QUOTE_ALL)
wr.writerow(my_list)
return '''
<html>
<head>
<title>This is just a testing template!</title>
</head>
<body>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
</body>
</html>
'''
if __name__ == "__main__":
app.run(host='0.0.0.0', debug=True)
To test from your Chrome console, you need first to go to http://127.0.0.1:5000/test (after that, jQuery will be available in your browser) then you run the following code: 要从您的Chrome控制台进行测试，您首先需要转到http://127.0.0.1:5000/test （之后，浏览器中将提供jQuery），然后运行以下代码：
$.ajax({
url: "http://127.0.0.1:5000/test",
method: "POST",
headers: {'Content-Type':'application/json'},
data: JSON.stringify({a: 10, b: 25}),
success: function(data){console.log('result: ' + data);}
});
If you have a Cross-origin issue, add also the below code to your app.py file: 如果您遇到跨域问题，请将以下代码也添加到您的app.py文件中：
@app.after_request
def after_request(response):
response.headers.add('Access-Control-Allow-Origin', '*')
response.headers.add('Access-Control-Allow-Headers', 'Origin, X-Requested-With, Content-Type, Accept')
response.headers.add('Access-Control-Allow-Methods', 'GET, PUT, POST, DELETE, OPTIONS')
return response
解决方案3
0 2016-09-02 18:40:04
似乎您在该HTML页面上的jQuery参考未加载或不正确，请在HTML页面的<head> here </head>部分中添加此参考。
<script src="https://code.jquery.com/jquery-3.1.0.js"></script>
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