将日期从一行复制到多行（Regex Notepad ++）

Question

I've been using Notepad++ for a while now but I haven't been able to figure this one out so any help is appreciated. I have this:

Day:2016-08-06

DATE/1850_01.xlsx

DATE/1850_02.xlsx

DATE/1850_03.xlsx

DATE/1850_04.xlsx

DATE/1850_05.xlsx

DATE/1850_06.xlsx

DATE/1850_07.xlsx

DATE/1850_08.xlsx

And I need a regex that takes the date in "Day:" (which here is 2016-08-06 but it varies, may be another random date like 2016-04-23 and so on) and replaces it on all of the "DATE". Basically this:

Day:2016-08-06

2016-08-06/1850_01.xlsx

2016-08-06/1850_02.xlsx

2016-08-06/1850_03.xlsx

2016-08-06/1850_04.xlsx

2016-08-06/1850_05.xlsx

2016-08-06/1850_06.xlsx

2016-08-06/1850_07.xlsx

2016-08-06/1850_08.xlsx

Answer 1

1. Here is aa regular expression find/replace approach:

   • Open Replace Dialog
   • Find What: (Day:([^[:space:]]+).*?)DATE
   • Replace With: \\1\\2
   • check regular expression
   • check . mathces newline . mathces newline
   • click Replace or Replace All

   This will replace the first occurence. You have to repeat Replace until all replacements are done (Replace All does not make a difference due to the nature of the RE). You can keep Alt-R pressed in the replace dialog, it is fast.

2. But there is another approach: Mark the date, copy it into clipboard, use a normal Replace, to replace DATE with the copied date from the first line, here Replace all will work. Its about the same keypresses and it is more straight forward.