Android频率振动

Question

I am working on an android application which detect the hand shaking (through accelerometer) and it modulates the vibration frequency based on shaking intensity.

I am able to get the tremor intensity through standard deviation (code below):

public void regressionCalc() {
    //Calculating sum values
    double sumZ;
    double meanZ;
    sumZ = 0;

    final TextView accZText = (TextView) findViewById(R.id.accelText);
    accZText.setText("");

    for (int r = 0; r < recArray.length; r++) {
        sumZ = sumZ + recArray[r];
    }
    meanZ = sumZ/recArray.length;

    //Calculating standard deviation
    double sumXu2; //this represents E((x-xbar)^2)
    sumXu2 = 0;
    for (int x = 0; x < recArray.length; x++) {
        sumXu2 += ((recArray[x]-meanZ)*(recArray[x]-meanZ));
    }
    double SD;
    SD = Math.sqrt(sumXu2/(recArray.length-1));
    tremorIntensity = SD;

    accZText.setText(String.format("%.2f", tremorIntensity) + "");
    accZText.setTextSize(80);
}

but I don't know how to work with vibration. I mean, I would like the phone vibration intensity decrease or increase based on the regression value.

Could anyone address me to a correct way? Thanks in advance.

Answer 1

The answer In my comment* shows how to make the device buzz according to a pattern:

Vibrator v = (Vibrator) getSystemService(Context.VIBRATOR_SERVICE);
long[] pattern = {0, 100, 1000, 300, 200, 100, 500, 200, 100};
v.vibrate(pattern, -1);

Since you already have a value for shaking intensity, the rest of the problem is just using your intensity value to generate values for pattern .

On the hardware level the buzzer is just on or off, so deciding what kind of changes to pattern best simulate changing intensity is a matter of trial and error. It might be as simple as making each on value proportional to tremorIntensity :

long[] pattern = {0, tremorItensity * factor, 100}

* Here it is.