将ID从一个表发布到另一个表

Question

I have two tables in db, input table nd output table. input table got two columns $ID (autoincreament), $question . table 2 got two columns $Q_ID, Answer .

i made a php page (1) where i printed out the table 1 content (QUESTION) and i added a text area to get answers from visitors, along with it i also added a echo "hidden" field for ID from table one.

Now this php page 1 redirects to php page 2, where i POST the text area input into the answer column in table 2. But unfortunately, the ID is not able to get posted in q_id column of table 2... I tried a lot but no hope..

My PHP script #1 as follows ::

<div class="name">
    <?php 
    $sql = "SELECT * FROM input";
    $result = $conn->query($sql);

    if ($result->num_rows > 0) { 
        $index = 0; 
        while($row = $result->fetch_assoc()) { 
            $index++; // stuff inside foreach goes here 
            ?>

            <div id="q">
                <B><big><font color= #ba4a00> Q:</font></big> <?php echo $row["question"]; ?> 

                <?php 
                echo '<button class="add" id="add_'.$index.'"><B>Add Answer</B></button>';
                echo '<form style="display:none;" name="answer_'.$index.'" method="post" action="output.php">'; 
                echo '<input type="hidden" name="questionid" value="<?php echo $row[id]?>"/>';
                echo '<textarea  type="text" class="addtext" name="addtext" required id="addtext_'.$index.'" placeholder="Please type your answer here.."  ></textarea>';
                echo '<button onClick="addsubmit('.$index.');" type="submit" id="addsubmit_'.$index.'" class="addsubmit"><B>Submit</B></button>';
                echo '</form>';
                ?>
            </div>
        <?php     
        }
    } else {
        echo "0 results";
    }
    $conn->close();
    ?>
</div>

My PHP script #2 as follows ::

<?php include('1.php'); ?>
<?php
    $servername  = "localhost";
    $dbusername = "root";
    $dbpassword = "*******";
    $dbname = "the_database";
    $addtext = $_POST['addtext'];
    $questionid = $_POST['questionid'];
    $date = date_default_timezone_set('Asia/Kolkata');
    $date = date('M-d,Y H:i:s');
    $conn = new mysqli ($servername, $dbusername, $dbpassword, $dbname);
    if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
    }
    $sql = "INSERT INTO output (question_id, answer, date)
    VALUES ('$questionid', '$addtext', '$date')";
    if ($conn->query($sql) === TRUE) {
    echo '<script language="javascript">';
    echo 'alert("Your Answer has been Succesfully posted")';
    echo '</script>';
    echo '<a href="1.php"></a>';
    }
    else {
    echo "ERROR" . $sql . "<br>" . $conn->error;
    }
    $conn->close();
 ?>

i want the respective question id to be passed to table 2 along with its answer.
Any help is greatly appreciated..

Answer 1

try enclosing id in double quotes in php 1:

echo '<input type="hidden" name="questionid" value="'.$row['id'].'"/>';

yip... looking a this a bit more closely you've got a bit of a problem with mixing single and double quotes in PHP #1.

for example, on this line the echo command ends after the second single quote after add_

echo '<button class="add" id="add_'.$index.'"><B>Add Answer</B></button>';

You need to use either single or double quotes consistently.

Answer 2

Give single-quote in $row['id'] . Change this <?php echo $row[id] >? to <?php echo $row['id'] >?

echo '<input type="hidden" name="questionid" value="'. $row['id'].'"/>';

Answer 3

Already you are echoing the form using the ECHO Attribute in the PHP but after that also you have echoed it and that is wrong.

You have to make the code like this.

echo '<input type="hidden" name="questionid" value="'. $row['id'].'"/>';

Try this and share the thought about the code..