[英]MySQL - Select max revision within nested statement
I would like to select max revision drawings from mysql table. 我想从mysql表中选择最大修订版图纸。 I can't use anything but nested select statement(?) (all conditions should be after 'SELECT * FROM
drawings
'). 除了嵌套的select语句(?)外,我什么也不能使用(所有条件应在“ SELECT * FROM
drawings
”之后)。
So, the 'drawings' table is: 因此,“图纸”表为:
+----+---------+-------------+-------+---------+---------------------+
| id | number | title |format | revision| date |
+----+---------+-------------+-------+---------+---------------------+
| 100| 022588 | some title | dwg | 1 | 2016-01-07 08:00:00 |
| 101| 022588 | some title | dwg | 2 | 2016-01-07 08:01:00 |
| 103| 022588 | some title | pdf | 3 | 2016-01-07 08:15:32 |
| 104| 022588 | some title | dwg | 3 | 2016-01-07 09:10:32 |
+----+---------+-------------+-------+---------+---------------------+
Result I would like to get is (same number, largest revision for appropriate format): 我想得到的结果是(相同编号,相应格式的最大修订版本):
| 103| 022588 | some title | pdf | 3 | 2016-01-07 08:15:32 |
| 104| 022588 | some title | dwg | 3 | 2016-01-07 09:10:32 |
And once more, I have (must) to start query with 'SELECT * FROM drawings
WHERE ......'. 再一次,我必须(必须)以“ SELECT * FROM
drawings
WHERE ......”开始查询。
Last thing I tried were: 我尝试的最后一件事是:
SELECT * FROM `drawings` WHERE `revision` IN ( SELECT MAX(`revision`) FROM `drawings` GROUP BY `number`, `format` ) GROUP BY `number`, `format` ORDER BY `number` DESC;
... and I got an proper pdf and wrong/lowest dwg (1 instead of 3). ...我得到了正确的pdf和错误/最低的dwg(从1改为3)。
If I read your question correctly, then you want to get drawings from each format
group having the maximum revision number in that group. 如果我正确阅读了您的问题,那么您希望从每个
format
组中具有最大修订号的图纸中获取图纸。 One approach uses a subquery to identify formats and their max revisions, and then uses that subquery to restrict the original drawings
table. 一种方法是使用子查询来标识格式及其最大修订版本,然后使用该子查询来限制原始
drawings
表。
SELECT t1.*
FROM drawings t1
INNER JOIN
(
SELECT format, MAX(revision) AS revision
FROM drawings
GROUP BY format
) t2
ON t1.format = t2.format AND
t1.revision = t2.revision
Follow the link below for a running demo: 请点击以下链接以获取正在运行的演示:
You can use a corelated subquery in the WHERE clause: 您可以在WHERE子句中使用相关的子查询:
SELECT d1.*
FROM `drawings` d1
WHERE `revision` = (
SELECT MAX(`revision`)
FROM `drawings` d2
WHERE d2.`number` = d1.`number`
AND d2.`format` = d1.`format`
)
ORDER BY `number` DESC;
See it on SQLFiddle 在SQLFiddle上查看
The query will return exactly one row for each combination of number
and format
with the highest revision. 对于具有最高修订版本的
number
和format
每种组合,查询将只返回一行。 I use that combination because of your original query: GROUP BY number, format
. 我使用该组合是因为您的原始查询是:
GROUP BY number, format
。 But you also wrote: "largest revision for appropriate format". 但是您还写道:“适用格式的最大修订版”。 In this case you should use:
在这种情况下,您应该使用:
SELECT d1.*
FROM `drawings` d1
WHERE `revision` = (
SELECT MAX(`revision`)
FROM `drawings` d2
WHERE d2.`format` = d1.`format`
)
ORDER BY `number` DESC;
I suggest: 我建议:
select d1.* from drawings d1 where d1.id in ( select max(d2.id) from drawings d2 group by d2.format ) 从图形d1中选择d1。*,其中d1.id在其中(从图形d2中按d2.format选择max(d2.id))
Querys using PrimaryKey are faster. 使用PrimaryKey的查询速度更快。 And you get the last record revision.
您将获得最后的记录修订。
This is the query: 这是查询:
select *
from drawings a inner join (select number, title, format,
max(revision) as revision
from drawings
group by number, title, format) b
on a.number = b.number and a.title = b.title and a.format = b.format
and a.revision = b.revision
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.