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结构C中的双重引用

[英]Double Dereference in struct C

I have the following code. 我有以下代码。 It seems the reading sequence is wrong. 看来阅读顺序是错误的。 Any help? 有什么帮助吗?

#include<stdio.h>
#include<stdlib.h>
#include<string.h>

typedef struct punct{
int x;
int y;
}COORD;

typedef struct nod{
COORD *coord;
struct nod *urm;
}NOD;
int main()
{
  NOD *head= malloc( sizeof(NOD) );
  scanf("%d", &head->coord->x );
  scanf("%d", &head->coord->y );
  printf("%d, %d", head->coord->x , head->coord->y);

  return 0;
}

I have successfully managed to access only the x field of the struct by using head->coord , and from what I can tell that's the issue with my code. 通过使用head->coord ,我已经成功地设法仅访问结构的x字段,从我可以看出这就是我的代码的问题。 I'm already on the first field of the first struct so I can't access x/y because of that. 我已经在第一个结构的第一个字段上,因此我无法访问x / y。

You did not initialize the coord variable so you shoud malloc some space for that too. 您没有初始化coord变量,因此也应该为此分配一些空间。

head->coord = malloc( sizeof (COORD) );

But in this case it might be best to put COORD in NOD instead of referencing to it! 但是在这种情况下,最好将COORD置于NOD而不是引用它!

So: 所以:

typedef struct nod{
   COORD coord;
   struct nod *urm;
}NOD;

You should only really make a pointer to it when you are going to swap the object a lot or when its a more complex object. 仅当要交换大量对象或对象更复杂时,才应该真正指向它。

You haven't initialized head->coord . 您尚未初始化head->coord Dereferencing uninitialized pointers result in undefined behaviour . 取消引用未初始化的指针会导致未定义的行为 You need to do something like: 您需要执行以下操作:

  head->coord = malloc( sizeof (COORD) );

You should also check the return value of malloc() for failures. 您还应该检查malloc()的返回值是否失败。

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