如何获取用户名并在登录时显示

Question

in this i wannna get the username who is logged in and display it in the home page when the username is correct and registered in database .should i use session and where to use it.how it is been done 在这种情况下，我想获取登录的用户名并在用户名正确并在数据库中注册时将其显示在主页中。我应该使用会话以及在何处使用它。如何完成

 <?php error_log("chk.php executing"); // Get values from form include 'config.php'; foreach ($_POST as $key => $value) { error_log($key); } //error_log($_POST['username']); $username=$_POST['username']; $password=$_POST['password']; // Insert data into mysql $qry = mysql_query("SELECT * FROM useraccount WHERE username='$username'"); if(!$qry) { die("Query Failed: ". mysql_error()); } else { $row=mysql_fetch_array($qry); if ($username==$row['username']) { if($username=='' || $password=='') { error_log("some fields are empty"); //header("Location:login.php?id=Some fields are empty"); // header("Content-Type: text/html"); // {echo "<b>Some fields are empty</b>";} } else if($username==$row['username'] && $password==$row['password']) { error_log("logged in"); header('Location: home.html'); // header("Content-Type: text/html"); // {echo "<b>User name password verified</b>";} //header("Location: home.html?id=$username"); } else { error_log("password is incorrect"); // header("Content-Type: text/html"); // {echo "<b>username already taken or your password is incorrect. Please try again</b>";} //header("Location:.php?id=username already taken or your password is incorrect. Please try again"); }} else error_log("username incorrect"); } mysql_close(); ?>

 html,body { margin:0px; height:100%; } .carousel-inner > .item > img, .carousel-inner > .item > a > img { width: 60%; margin: auto; } .content { width:100%; height:400px; } .signup { height:500px; } .footer { position:relative; background-color:black; }

  <!DOCTYPE html> <html lang="en"> <head> <title>ASK</title> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, initial-scale=1"> <link rel="stylesheet" type="text/css" href="boot.css"> <link rel="stylesheet" href="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css"> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script> <script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/js/bootstrap.min.js"></script> </head> <body> <div class="jumbotron"> <div class="container"> <div class="row"> <div class="col-md-6"> <h1>school name</h1> </div> <div class="col-md-6"> <img src="../project/photo/l.png" height="150px"/> </div> </div> </div> </div> <nav class="navbar navbar-inverse navbar-fixed-top"> <div class="container-fluid"> <div class="navbar-header"> <button type="button" class="navbar-toggle" data-toggle="collapse" data-target="#myNavbar"> <span class="icon-bar"></span> <span class="icon-bar"></span> <span class="icon-bar"></span> </button> <a class="navbar-brand" href="#mynavbar">schoolName</a> </div> <div class="collapse navbar-collapse" id="myNavbar"> <ul class="nav navbar-nav"> <li class="active"><a href="#">Home</a></li> <li><a href="about.html" target=_self>About Us</a></li> <li><a href="infra.html" target=_self>Infrastructure</a></li> <li class="dropdown"> <a class="dropdown-toggle" data-toggle="dropdown" href="">Administration<span class="caret"></span></a> <ul class="dropdown-menu"> <li><a href="stlogin.html">staff login</a></li> <li><a href="stdetails.html">staff details</a></li> <li><a href="class.html">class handling</a></li> </ul> </li> </ul> <ul class="nav navbar-nav navbar-right"> <li><a href="#"><span class="glyphicon glyphicon-user"></span> Sign Up</a></li> <li><a href="#"><span class="glyphicon glyphicon-log-in"></span> Login</a></li> </ul> </div> </div> </nav> <div class="container"> <form class="form-horizontal" action="chk.php" method="POST"> <div class="form-group"> <div class="col-xs-3"> <label for="username">Username:</label> <input name="username" type="username" class="form-control" id="username" placeholder="Enter username"> </div></div> <div class="form-group"> <div class="col-xs-3"> <label for="pwd">Password:</label> <input name="password" type="password" class="form-control" id="password" placeholder="Enter password"> </div></div> <!-- <div class="checkbox"> <label><input type="checkbox"> Remember me</label><br> </div> --> <button type="submit" class="btn btn-default">Submit</button><br> </form> </div> <div class="footer navbar-fixed-bottom"> <p> Copyrights@ &copy;WWW.schools.com</p> </div> </body> </html>

Answer 1

You can use SESSION . 您可以使用SESSION 。 You have to use session_start() in every files that you want to display the username 您必须在要显示用户名的每个文件中使用session_start()

    else if($username==$row['username'] && $password==$row['password']) {
                $_SESSION['username'] = $username; // store username name in session
                error_log("logged in");
                header('Location: home.html');
                // header("Content-Type: text/html");
                // {echo "<b>User name password verified</b>";}
                header("Location: home.php?id=$username"); // redirect to home.php page

You can simply display the username by echo $_SESSION['username']; 您可以通过echo $_SESSION['username'];简单地显示用户echo $_SESSION['username']; Don't forget to add session_start(); 不要忘记添加session_start(); in your home.php. 在您的home.php中。 For more info please refer to this link http://php.net/manual/en/function.session-start.php 有关更多信息，请参考此链接http://php.net/manual/en/function.session-start.php

Answer 2

first of all when username store in session on login time 


  <?php

session_start();

 - List item

error_log("chk.php executing"); // Get values from form  include 'config.php';

foreach ($_POST as $key => $value) {    error_log($key); } //error_log($_POST['username']); $username=$_POST['username']; $password=$_POST['password']; // Insert data into mysql  $qry   = mysql_query("SELECT * FROM useraccount WHERE username='$username'"); if(!$qry) { die("Query Failed: ". mysql_error()); } else {

$row=mysql_fetch_array($qry);

if ($username==$row['username']) {
    if($username=='' || $password=='') {
        error_log("some fields are empty");
        //header("Location:login.php?id=Some fields are empty");
        // header("Content-Type: text/html");           // {echo "<b>Some fields are empty</b>";}
    } else if($username==$row['username'] && $password==$row['password']) {
        error_log("logged in");

       $_SESSION['username']=$row['username'];
        header('Location: home.html');
        // header("Content-Type: text/html");           // {echo "<b>User name password verified</b>";}
        //header("Location: home.html?id=$username");
    } else {
        error_log("password is incorrect");
        // header("Content-Type: text/html");           // {echo "<b>username already taken or your password is incorrect. Please try again</b>";}
        //header("Location:.php?id=username already taken or your password is incorrect. Please try again");
    }}
    else
        error_log("username incorrect"); } mysql_close(); ?>

Another page we get this username and we change file name home.html to home.php 在另一页上，我们获得该用户名，并将文件名home.html更改为home.php。

home.php home.php

echo $_SESSION['username']; echo $ _SESSION ['username'];

?> output username print this page ？>输出用户名打印此页

Answer 3

You should use session_start(); 您应该使用session_start(); After successfully login,you can post username or email like this- 成功登录后，您可以发布用户名或电子邮件，如下所示：

<?php
include_once'dbconnect.php';
$res=mysql_query("SELECT * FROM users WHERE user_id=".$_SESSION['user']);
$userRow=mysql_fetch_array($res);
//print logged in user's email as saved in database
echo $userRow['email'];
////print logged in user's username as saved in database
echo $userRow['username'];
?>

This is as per my database where- 这是根据我的数据库，其中-

'dbconnect.php'is connection file. “ dbconnect.php”是连接文件。
'users' is tablename. “用户”是表名。

Answer 4

You can use session_start(); 您可以使用session_start(); and store the username into it. 并将用户名存储到其中。

//Initialize the session:
session_start();
<!doctype html>
<head>
.
.
.
</head>
<body>
.
.
<?php
$q = "SELECT * FROM useraccount WHERE username='$username'";
$r = $mysqli->query($q);
if ($r->num_rows == 1) {
$_SESSION = $r-> fetch_array(MYSQLI_ASSOC); 
}
?>
.
</body>
</html>

You can take a look at my site for that same query at hiteachers.com 您可以在hiteachers.com上针对我的相同查询查询我的网站

如何获取用户名并在登录时显示

问题描述

4 个解决方案

解决方案1
1 2016-09-06 05:24:20

解决方案2
1 2016-09-06 05:25:50

解决方案3
0 2016-09-06 05:40:26

解决方案4
0 2016-09-06 07:30:10

如何获取用户名并在登录时显示

问题描述

4 个解决方案

解决方案1 1 2016-09-06 05:24:20

解决方案2 1 2016-09-06 05:25:50

解决方案3 0 2016-09-06 05:40:26

解决方案4 0 2016-09-06 07:30:10

解决方案1
1 2016-09-06 05:24:20

解决方案2
1 2016-09-06 05:25:50

解决方案3
0 2016-09-06 05:40:26

解决方案4
0 2016-09-06 07:30:10