Haskell：将字节字符串转换为[word8]

Question

my intent is to convert a bytestring to a List of Word8 in haskell in order to get access to the LSB for each byte .

any idea how to achieve that ?

Answer 1

unpack :: ByteString -> [Word8] 

http://hackage.haskell.org/package/bytestring-0.10.8.1/docs/Data-ByteString.html#v:unpack

Also consider whether you can skip the intermediate list, and directly use foldl' or some related fold.