创建c＃异常而不抛出它

Question

Is there a way better than what I'll have written below to get an exception properly set like when thrown?

try {
throw new Exception("Blah");
}
catch (Exception exe) {
Assert.NotNull(exe.StackTrace);
DoSomeWork(exe);
// throw;
}

Answer 1

The short answer is : NO.

The System.Exception properties are filled in when it is thrown :

By default, the stack trace is captured immediately before an exception object is thrown. Use Environment.StackTrace to get stack trace information when no exception is being thrown.

So if you really need an exception object in the state it is after being thrown you have no other good way but to throw and catch it.

Still do not drop off the main question: do you really need the exception object?

If you've got a method that has System.Exception as an input parameter and you need a StackTrace inside, think of these possible solutions:

1. Method overload with an optional StackTrace input parameter.
2. A successor of System.Exception with a hiding StackTrace property which memorizes the StackTrace when the object is created not thrown.

3. As the last resort you could make an extension method for the System.Exception class which "populates" an instance of the System.Exception:

    private void MyCode() { Exception exe = new Exception("Blah"); exe.Populate(); DoSomeWork(exe); } public static void Populate(this System.Exception source) { try { throw source; } catch { } }