[英]How to get a max string length in nested lists
They is a follow up question to my earlier post (re printing table from a list of lists)它们是我之前帖子的后续问题(从列表列表中重新打印表格)
I'm trying t get a string max value of the following nested list:我正在尝试获取以下嵌套列表的字符串最大值:
tableData = [['apples', 'oranges', 'cherries', 'banana'],
['Alice', 'Bob', 'Carol', 'David'],
['dogs', 'cats', 'moose', 'goose']]
for i in tableData:
print(len(max(i)))
which gives me 7, 5, 5. But "cherries" is 8这给了我 7、5、5。但是“樱桃”是 8
what a my missing here?我在这里想念什么? Thanks.
谢谢。
You've done the length of the maximum word .你已经完成了最大 word的长度。 This gives the wrong answer because words are ordered lexicographically :
这给出了错误的答案,因为单词是按字典顺序排列的:
>>> 'oranges' > 'cherries'
True
What you probably wanted is the maximum of the lengths of words :您可能想要的是单词的最大长度:
max(len(word) for word in i)
Or equivalently:或等效地:
len(max(i, key=len))
In string operations max
will Return the maximum alphabetical character from the string, not in basics of length.在字符串操作中
max
将从字符串中返回最大的字母字符,而不是长度的基础。 So you have to do something like this.所以你必须做这样的事情。
len(max(sum(tableData,[]),key=len))
sum(tableData,[])
will convert the list of list
to list
this helps to iterate through the list of list. sum(tableData,[])
将转换成list of list
,以list
此列表通过的名单有助于迭代。
Length in each row每行长度
In [1]: [len(max(i,key=len)) for i in tableData]
Out[1]: [8, 5, 5]
See the difference,看到不同,
In [2]: max(sum(tableData,[]))
Out[2]: 'oranges'
In [3]: max(sum(tableData,[]),key=len)
Out[3]: 'cherries'
You were printing the length of the max element in each row.您正在打印每行中最大元素的长度。 Python computes the
max
string element as the one that is seen last in a dictionary (lexicographic sorting). Python 计算
max
字符串元素作为字典中最后出现的元素(字典排序)。 What you want instead is max(len(s) for s in i)
instead of len(max(i))
你想要的是
max(len(s) for s in i)
而不是len(max(i))
for row in tableData:
print(max(len(s) for s in row))
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