newtonsoft json反序列化错误处理：部分反序列化

Question

Is there way to deserialize invalid json?

For example, next JSON deserialization will fail with JsonReaderException

{
 'sessionId': 's0j1',
 'commandId': 19,
 'options': invalidValue // invalid value
}

because options property value is invalid.

Is there a nice way to get sessionId and commandId values even if options value is invalid?

I know it's possible to handle errors during deserialization ( http://www.newtonsoft.com/json/help/html/SerializationErrorHandling.htm )

var json = "{'sessionId': 's0j1', 'commandId': 19, 'options': invalidValue}"; 

var settings = new JsonSerializerSettings
{
    Error = delegate(object sender, ErrorEventArgs args)
    {
      args.ErrorContext.Handled = true;
    }
});
var result = JsonConvert.DeserializeObject(json, settings);

Bit it will result in result = null .

Answer 1

You can do it with JsonReader .

Example code:

var result = new Dictionary<string, object>();

using (var reader = new JsonTextReader(new StringReader(yourJsonString)))
{
    var lastProp = string.Empty;
    try
    {
        while (reader.Read())
        {
            if (reader.TokenType == JsonToken.PropertyName)
            {
                lastProp = reader.Value.ToString();
            }

            if (reader.TokenType == JsonToken.Integer || 
                reader.TokenType == JsonToken.String)
            {
                result.Add(lastProp, reader.Value);
            }
        }
    }

    catch(JsonReaderException jre)
    {
        //do anything what you want with exception
    }
}

Note, that there is try..catch block as when JsonReader meets invalid character it throws JsonReaderException on reader.Read()