Java WebApp无法从jar加载.properties

Question

I am building a web app based on Maven multi modules. So My project structure is like the following:

/module1
    /src/main/java
      package/Module1.java
    /src/main/resources
      conf/i18n_en.properties
/webapp
    /src/main/java
      package/Web.java
    /src/main/resources
      conf/i18n_en.properties
    /src/main/webapp

I have different properties("i18n_en.properties") for I18N in every module, I load the properties file in code and get the information. It seems good running in single module test.

private ResourceBundle rb;
String filename = BASE_NAME + "_" + LANG + ".properties";
InputStream in = Thread.currentThread().getContextClassLoader().getResourceAsStream(filename);
        if(in == null) {
            in = c.getResourceAsStream(filename);
        }
        if (in == null) {
            in = c.getClassLoader().getResourceAsStream(filename);
        }

        if (in != null) {
                rb = new PropertyResourceBundle(in);
         }

However, when I started tomcat with IDEA, the program only load the properties in webapp! Just cannot find the "Module1" s properties!

I think it's the problem of loading properties from innner jar. For the deployed directory is as following:

/WEB-INF
  /classes
    /conf/i18n_en.properties  (from webapp)
  /lib
    /Module1.jar  (has it's own properties in it)

I was really confused. I searched every thing related for a long time and i found some thing similar, but I just can't solve the problem. I think I have done what they said. Java WebApp: Loading resource from .jar located in WEB-INF

I don't know where is the problem, There must be some ways to load the properties inner jar. Anyone knows anything , please help me, thank you very much~

Answer 1

In jar file, you can't use ClassLoader() method to find an element.
You can use:

try {
      URL url2 = new URL(this.getClass().getProtectionDomain().getCodeSource().getLocation().toURI().toString()+your path to file in structre);
      InputStream in = url2.openStream();
} catch (URISyntaxException ex) {
      Logger.getLogger(PrepareGUI.class.getName()).log(Level.SEVERE, null, ex);
}