如何在python列表中获取对象的选定属性？

Question

How do I create a list with the selected attributes of an object in python ? Using list comprehensions.

Eg:

My object A has

A.name
A.age
A.height

and many more attributes

How do I create a list [name,age]

I can do it manually but it looks ugly:

l=[]
l.append(A.name)
l.append(A.age)

but I am looking for a shortcut.

Answer 1

Why not just [A.name, A.age] ? list literals are simple. You could use operator.attrgetter if you need to do it a lot , though it returns tuple s when fetching multiple attributes, not list s, so you'd have to convert if you can't live with that.

Answer 2

What you're looking for is operator.attrgetter

attrs = ['name', 'age'] 
l = list(operator.attrgetter(*attrs)(A))

Answer 3

You can collect them going through all A class attributes and checking if they aren't method or built-in.

import inspect

def collect_props():
    for name in dir(A):
        if not inspect.ismethod(getattr(A, name)) and\
           not name.startswith('__'):
            yield name

print list(collect_props())