JMapViewer，获取OSM地图比例，Java

Question

In my Java application I am using JmapViewer; the map is drawn on the jPanel. Is it possible to get the map scale corresponding to the current zoom level? The map is based on the well-known Mercator projection:

X = R * lon * cos(lat1);
Y = R * log(tan(lat/2 + 45)), lat1 = 0;

The projection is conformal, so the local linear scale is independent of the direction. My idea uses two points sharing the same parallel:

 Point p1 = new Point(0,0);
 Point p2 = new Point(100,0);

 final double dlon = getPosition(p2).getLon() - getPosition(p1).getLon();
 final double scale = 6380000 * abs(dlon) * PI / 180 / 100;  //scale = (R * dlon)/||p1-p2||

An improvement: the initial point p1 may be a center of the view.

Point p1 = new Point(jPanel1.width()/2,jPanel1.height()/2);
Point p2 = new Point(jPanel1.width()/2  + 100, jPanel1.height()/2);

The pixel coordinates are evaluated "in meters"; the formula lacks the pixel size...

Answer 1

The JMapViewer method getMeterPerPixel() returns the number of meters per pixel at the current zoom level. It uses TileSource::getDistance , which "Gets the distance using the spherical law of cosines ." In org.openstreetmap.gui.jmapviewer.Demo , you can see how the value varies inversely with the zoom; level 10 and 98.5 meters/pixel are shown below. See OsmMercator::getDistance for a typical implementation.