regexp \ k <name + 0>中的“+0”是什么意思？

Question

I'm new to Regular Expressions in Ruby, and I can't seem to find any solid documentation on what \\k<name+0> means. It's the +0 part that I'm not getting.

Here's an example - this Regexp matches palindromes:

\A(?<p>(?:(?<l>\w)\g<p>\k<l+0>|\w))\z

When I remove the +0 in \\k<l+0> it no longer matches correctly.
My tests:

>> /\A(?<p>(?:(?<l>\w)\g<p>\k<l+0>|\w))\z/.match "aabbcdcbbaa" 
#=> #<MatchData "aabbcdcbbaa" p:"aabbcdcbbaa" l:"c">

>> /\A(?<p>(?:(?<l>\w)\g<p>\k<l>|\w))\z/.match "aabbcdcbbaa" 
#=> nil

All I've done is remove the +0 . I haven't yet found any documentation or example of this, can anyone point me in the right direction?

Answer 1

The \\k<l+0> works together with the (?<l>\\w)

The match of (?<l>\\w) is stored in the capturing group named 'l'

\\k<l+0> Matches the same text that was matched by the named capturing group 'l' when it was at the same recursion level as this backreference is now