在python3中输出十六进制值

Question

I am writing shellcode exploits with python3. However, when I try and output some hex bytes. eg using the line - python3 -c 'print("\\x8c")' | xxd python3 -c 'print("\\x8c")' | xxd

The value in xxd is c28c , rather than the expected 8c

This issue does not occur in python2.

Answer 1

Your issue arises because Python 3 handles strings as Unicode, and print expects Unicode to encode some output for your terminal. Try the following to bypass this:

python3 -c "import sys; sys.stdout.buffer.write(b'\x8c')" | xxd