如何在悬停后从下到上显示下拉菜单滑块效果？

Question

I have display drop down menu slider effect from bottom to top after hover with linearly and all drop down text should be display left align. I tried some code but when i hovered first menu my second menu displaying on right side.would you help me in this?

HTML

<div class="right-menu-bar">
        <ul class="main-menu">
            <li><a href="">Menu</a>
                <ul>
                <li><a href="">menu1 details</a></li>
                <li><a href="">menu1 details</a></li>
                <li><a href="">menu1 details</a></li>
                </ul>
            </li>
<li><a href="">Menu</a>
            <ul>
            <li><a href="">menu1 details</a></li>
            <li><a href="">menu1 details</a></li>
            <li><a href="">menu1 details</a></li>
            </ul>
        </li>
        </ul>
    </div>

CSS

.right-menu-bar ul.main-menu > li
{
    float: left;
    margin: 15px;
    font-size: 16px;
}
li ul
{
    list-style: none;
    background: #3498db;
    z-index: 2;
    font-size: 16px;
    padding:0 ;

}

li ul li
{

    text-transform: capitalize;
}

.main-menu li > ul {
    display:none;

}

.main-menu li:hover > ul {
    display:block;
}


li ul li a{
  text-decoration: none;
  color: #fff;
  padding: 10px 50px;
  display:block;

text-align: left !important;
}

 li ul li a:hover{
  background-color:#5dade2;
  text-decoration: none;
  color: #000;
}

Answer 1

You can do this by applying position: absolute; to the menus that appear, like this:

.main-menu li:hover > ul {
    display:block;
    position: absolute;
}

Working Fiddle

Answer 2

I thought your problem is stop the second menu slide to right when hover the 1st menu. so adding the position:absolute property to dropdown menu to avoid the second menu sliding.

Now I am adding sideDown() and slideUp() to show or hide the dropdown on menu hover Try below code.

  //Hide and Show The Sub Menus $(".jquery-test ul li.menu-list").hover(function(){ $(this).find('ul').stop().slideDown(); },function(){ $(this).find('ul').stop(true,true).slideUp(); }); 

 .jquery-test ul.menu li.menu-list{display:inline-block;padding-right:20px;} .jquery-test ul{list-style:none;padding-left:10px;} .jquery-test ul.menu li.menu-list ul.submenu {display:none;} .jquery-test ul.menu li.menu-list ul.submenu{position:absolute;} .jquery-test ul.menu li.menu-list ul.submenu li{position:relative;left:0px;} .jquery-test ul li a{text-decoration:none;color:#000;} 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script> <div class="jquery-test"> <ul class="menu"> <li class="menu-list"><a href="#">Menu1</a> <ul class="submenu"> <li><a href="#">Menu1.0</a></li> <li><a href="#">Menu1.1</a></li> <li><a href="#">Menu1.2</a></li> <li><a href="#">Menu1.3</a></li> </ul> </li> <li class="menu-list"><a href="#">Menu2</a> <ul class="submenu"> <li><a href="#">Menu2.1</a></li> <li><a href="#">Menu2.2</a></li> <li><a href="#">Menu2.3</a></li> <li><a href="#">Menu2.4</a></li> </ul> </li> <li class="menu-list"><a href="#">Menu3</a> <ul class="submenu"> <li><a href="#">Menu3.0</a></li> <li><a href="#">Menu3.1</a></li> <li><a href="#">Menu3.2</a></li> <li><a href="#">Menu3.3</a></li> </ul> </li> </ul>