我想在 python 中编写一个名为 cont() 的函数，它发送一条消息“继续”并且不应该带任何参数

Question

i want to write a function in python named cont() which sends a message "continue" and which should take no argument.the function should print the message yes,y or Y.then return true otherwise false. i have done it but there is an error.

def cont():
    x = input("enter any word of your choice")
    for letter in 'x':
        if letter == '[0]':
            a = input ("continue")
            if a == 'yes' == 'y' == 'Y' :
                continue
            print 'current letter will be:',letter
        else:
            print x

if __name__=="__main__":
    cont()

Answer 1

Sadly the code that you supplied and the description that you wrote, do not agree with each other. There is no attempt to return any value, indeed, there is nothing to suggest what the decision of True or False would be based upon.
Assuming that you are using python 2.7, this should get you started:

def cont():
    x = raw_input("Enter any word of your choice: ")
    for letter in x:
#    if letter == '[0]':
        a = raw_input ("Continue? ")
        if a == 'yes' or a == 'y' or a == 'Y' :
#            continue
            print 'Current letter will be:',letter
        else:
            print x
            break
if __name__ == '__main__':
    cont()

I have no idea what you were attempting to do with the if letter == '[0]': or the continue lines, so I have commented them out. If you wish to return a value, simply return True or return False at the point of your choosing in the code. The other option is to set a variable to True or False and then, as the last statement of cont() use the return keyword with the variable.

Note: if you are using python3 the raw_input becomes input and the print commands become print()