使用SAX Parser解析XML时需要获取element标签的值

Question

Grabbing an XML file off of the internet and feeding it's data into a database. Most of it works just fine. But I have a problem with xml tags having the same name but different values attached.

So, we have an xml file like this:

 <Overtag> <Tag> Name </Tag> <SubTag> TextSubTag </SubTag> <TagWithValue value="SomeValue"> TextTagWithValue </TagWithValue> </Overtag> <Overtag>... 

I can set up a NodeList by Overtag. I can get a nodeist of Overtag's Children which I call Children.

So, I run this over a for loop - for(int nN=0; nN

I grab the Text of the Tags themselves:

String sTag = Children.item(nN).getNodeName();

I can even grab the text between the Tags: Children.item(nN).getTextContent()

BUT I need to organize this text based on the value.

What command can I use to get "SomeValue" if nN = the childlist number for (in this case 2)?

As in: Children.item(nN).?

Answer 1

Found it...

if using NodeList to list out your xml tags, you need to return it to an element, then use getAttribute; so if the tag is (assuming your list with TagWithValue in it is a NodeList called Children):

Element eChild = (Element) Children.item(nN);
                String sAtt = eChild.getAttribute("value");`

This will give you sAtt = "SomeValue". Sorry to waste space by posting then finding the answer two hours later; hopefully someone else finds this useful.