Flask-Marshmallow通过API公开DB内容的问题

Question

I am developing a API which will return entries from a Database. I am using Flask-SQLAlchemy, Flask-Marshmallow, Flask-Admin and Docker to package it all up.

In one file Packages.py I have the following code regarding the database. The class PckagesSchema is the class I've added when trying to get Flash-Marshmallow working.

class Packages(db.Model):
    id = db.Column(db.Integer, primary_key=True, autoincrement=True)
    trackingnumber = db.Column(db.String(15))
    email = db.Column(db.String(80))
    localid = db.Column(db.String(80))

class PackagesSchema(ma.ModelSchema):
    class Meta:
        model = Packages

The in the main file I have the following snippets of code

from app.models import Packages, PackagesSchema
packages_schema = PackagesSchema()
db.create_all()

and then further down the part which will deal with API GET Requests.

@app.route('/packages', methods=['GET'])
def get_packages():
    result = packages_schema.dump(Packages).data
    return jsonify(result)

at the moment this returns:

{
  "email": "Packages.email", 
  "localid": "Packages.localid", 
  "trackingnumber": "Packages.trackingnumber"
}   

However, there is definitely something in the database as the Flask-Admin app displays its.

This is my first day working with Flask-Marshmallow so I am not that experienced at all and would appreciate any help. I have read https://flask-marshmallow.readthedocs.io/en/latest/ but still stuck.

Answer 1

I just brushed up a little on marshmallow:

@app.route('/packages', methods=['GET'])
def get_packages():
    packages = Packages.query.all()
    result = packages_schema.dump(packages).data
    return jsonify(result)

Should give you everything in there. If you are returning many records, you need to add packages_schema = PackagesSchema(many=True) .

Also, not sure what version of flask you are running... but pre the latest release, I dont think jsonify would work here since you could not call it on a list. Juts a heads up.