如何防止Django的label_tag函数转义标签？

Question

Example:

>>> example.label
&#x3bb;<sub>blabla</sub>
>>> example.label_tag()
[...]&amp;#x3bb;&lt;blabla&gt;[...]

Even calling mark_safe(example.label) before label_tag() does not prevent Django from escaping the HTML. How can I get label_tag() to return unescaped labels?

Answer 1

There is a comment in the code for label_tag

Wraps the given contents in a <label>, if the field has an ID attribute.
contents should be 'mark_safe'd to avoid HTML escaping. If contents
aren't given, uses the field's HTML-escaped label.

So

example.label_tag(contents=mark_safe(example.label))

Should work.. I can't see another way around this problem

Answer 2

Try this:

            from HTMLParser import HTMLParser

            h = HTMLParser()
            unescaped = h.unescape(example.label_tag())
            print unescaped

Answer 3

You have to mark the label as safe when you define the field.

class MyForm(forms.Form):

    example = forms.Field(label=mark_safe('&#x3bb;<sub>blabla</sub>'))

Example:

>>> f = MyForm({'example': 'foo'})
>>> str(f)
'<tr><th><label for="id_example">&#x3bb;<sub>blabla</sub>:</label></th><td><input id="id_example" name="example" type="text" value="foo" /></td></tr>'