PHP while while语句中的while语句？

Question

Db db2 Code Sample so far only lists all the posts but shows only one Comment ? Code I have so far only shows one comment ?

Please anyone with assistance I really need help am a noob at coding and trying my best. Thank you in advance

<?php
include("../db/db.php");
{

    /*if(isset($_POST["TimeLine"])){*/
    $queryposts = "SELECT * FROM post";
    $run_query = mysqli_query($con,$queryposts);
    while($row = mysqli_fetch_array($run_query)){
        $post_id = $row["post_id"];
        $uid = $row["user_id"];
        $content = $row["content"];
        $like = $row["total_like"];
        $date = $row["date_created"];
        $uidpic = $row["profilepic"];
        $email = $row["email"];
        $pImage = $row["postimage"];
        $pVideo = $row["video"];
        echo "<b>POST: <b/><hr />".
            $content."<hr >"
        ;


        $querycomment = "SELECT * FROM comment WHERE comment_id = $post_id";
        $run_queryb = mysqli_query($con,$querycomment);
        while($row = mysqli_fetch_array($run_queryb)){
            $ComId = $row["comment_id"];
            $Comment = $row["comment"];
            $ComDate = $row["comment_date"];
            $ProfilePicpost = $row["profilepic"];
            echo "<b>Comment: <b/><hr />".
                $Comment."<hr >"
            ;
        }
    }
}

Answer 1

You are overwriting same variable $row in inner loop. Change its name to anything else.

$queryposts = "SELECT * FROM post";
$run_query = mysqli_query($con,$queryposts);

while($posts = mysqli_fetch_array($run_query)){

    // Your post related code
    $post_id = $posts["post_id"];
    $uid = $posts["user_id"];
    // Use $posts instead of $row

    $querycomment = "SELECT * FROM comment WHERE comment_id = $post_id";
    $run_queryb = mysqli_query($con,$querycomment);

    while($comments = mysqli_fetch_array($run_queryb)){

        // Your comment related code
        $ComId = $comments["comment_id"];
        $Comment = $comments["comment"];
        // Use $comments instead of $row

    }
}