[英]Define a sequence recursively in Java
Need help with this problem, I am very bad at recursion. 在这个问题上需要帮助,我在递归方面很不好。 I need to write a method that does this:
我需要编写一个执行此操作的方法:
The input variable X is an integer between 1 and 50. The function should return as Y the X-th term of a sequence defined recursively by: 输入变量X是1到50之间的整数。该函数应以Y形式返回由以下项递归定义的序列的第X个项:
f(1) = 1 f(2) = 3 f(X) = 2*f(X-1) – 2*f(X-2) for X = 3,4,5,...
Your function code should use recursion (not a loop) 您的函数代码应使用递归(而不是循环)
TBH I dont even know where to get started. TBH我什至不知道从哪里开始。 Any help would be appreciated.
任何帮助,将不胜感激。 Here is my current code:
这是我当前的代码:
package p1parta;
import java.util.Scanner;
public class RecursiveSeq
{
public static void main(String args[])
{
System.out.println("Please enter a number:");
Scanner input = new Scanner(System.in);
int x = input.nextInt();
System.out.println(sequence(x));
}
public static int sequence(int x)
{
if(x == 1){
return 1;
}
if (x == 2){
return 3;
}
return 2 * sequence(x - 1) - 2 * sequence(x - 2);
}
}
I tried to implement the solution shown but the output I get from the program do not match what I am calculating by hand. 我尝试实现所示的解决方案,但是从程序中获得的输出与我手工计算的结果不匹配。 In fact just testing inputs 3,4,5,and 6 The only one that matches is 5
实际上,仅测试输入3、4、5和6,唯一匹配的输入是5
Your problem is a perfect use case for recursion. 您的问题是一个完美的递归用例。 In general the recursive pattern is:
通常,递归模式为:
func(context)
if simple case
return simple answer
else
call func(simpler context)
and return combined results
Have a go at implementing using this pattern and come back if you have issues. 尝试使用此模式实施,如果有问题请回来。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.