当两件事正确时如何打印信息，以及在这两件事不正确时如何使用输入功能

Question

I am doing a controlled assessment. I have this code :

# user Qualifications
print("\nQualification Level")

print("\n""\"AP\" = Apprentice",
      "\n\"FQ\" = Fully-Qualified")
user_qual = input("Enter you Qualification Level: ")

When the user_qual is equal to AP or FQ I want to print "correct". But when the user_qual is not equal to either AP or FQ , I want to print an error message and re-ask the user_qual input question. However, I tried many different ways but couldn't do it.

Please just give a simple solution and nothing complicated. I am just a beginner and learning the basics.

Answer 1

You can try defining the qualification levels within a variable. In this simple case a tuple suffices, but if there were to be more qualification levels, a dictionary would make more sense.

qualification_levels = ('AP', 'FQ')
print("\n""\"AP\" = Apprentice",
      "\n\"FQ\" = Fully-Qualified")
user_qual = input("Enter you Qualification Level: ")
if user_qual in qualification_levels:
    print('correct!')
else:
    print('ERROR!!!')

Answer 2

You need to turn your code into a function so it can be called again, if the criteria are not met:

def prompt():
    # user Qualifications
    print('\nQualification Level')
    print('\n"AP" = Apprentice\n"FQ" = Fully-Qualified')

    user_qual = input('Enter you Qualification Level: ')

    if user_qual not in ('AP','FQ'):
        prompt() # Criteria not met, so ask again
    print('Correct!') # Criteria met, don't ask again


# Call the function the first time
prompt()

As @IanAuld mentions in the comments, if you want to allow users to provide the answer (ie. AP) in a case insensitive manner (so users can type 'ap' instead), you would want to convert the case before evaluating it, like so:

if user_qual.upper() not in ('AP','FQ'):
    ...rest of code...