[英]Add Markers to Google Maps from JS Array
I have the array: 我有数组:
var stops = [];
stops[1] = {name:'One', lat:51.9219465100951 ,long:-8.61797176722262};
stops[2] = {name:'Two', lat:51.9270744 ,long:-8.6105043};
stops[3] = {name:'Three)', lat:51.9254898 ,long:-8.6100269};
I'm trying to loop through and display these markers on a map... 我正在尝试遍历并在地图上显示这些标记...
function initMap() {
map = new google.maps.Map(document.getElementById('map'), {
center: {lat: 51.933596, lng: -8.578540},
zoom: 14,
mapTypeId: 'hybrid'
});
for(var i=0; i<=stops.length; i++){
var mypos = {stops[i].lat, stops[i].long};
var marker = new google.maps.Marker({
position: mypos,
map: map,
title: stops[i].name
});
}
}
No markers are being drawn on the map. 地图上没有标记。
I'm getting an unexpected token error of [ on the following line. 我在下一行收到[的意外令牌错误。 var mypos = {stops[i].lat, stops[i].lng};
var mypos = {stops [i] .lat,stops [i] .lng};
I've changed this around but still can't get it to work. 我已对此进行了更改,但仍然无法正常工作。
you are creating an invalid object when all you really need to do is pass stops[i]
for your position 当您真正需要做的只是通过
stops[i]
,您正在创建一个无效的对象
var mypos = {stops[i].lat, stops[i].lng};
should be 应该
var mypos =stops[i];
But there is another issue , array indexing is zero based but you start at one 但是还有另一个问题,数组索引从零开始,但是您从一个开始
A much simpler way to create the initial array would be 创建初始数组的一种简单得多的方法是
var stops = [
{name:'One', lat:51.9219465100951 ,lng:-8.61797176722262},
{name:'Two', lat:51.9270744 ,lng:-8.6105043},
{name:'Three)', lat:51.9254898 ,lng:-8.6100269}
];
Note that the property name long
has been changed to lng
to match what map script uses 请注意,属性名称
long
已更改为lng
以匹配地图脚本使用的属性
mypos needs to be: mypos必须是:
var mypos = {lat: stops[i].lat, lng: stops[i].long};
Without "lat:" and "lng:" you're trying to declare an object as if it's an array. 如果没有“ lat:”和“ lng:”,则试图将对象声明为数组。 'position' expects either a LatLngLiteral (see above) or a LatLng object, which is declared like this:
'position'期望使用LatLngLiteral(请参见上文)或LatLng对象,其声明如下:
var mypos = new google.maps.LatLng(stops[i].lat, stops[i].long};
Check the code example: 检查代码示例:
$(window).load(function() { $(document).ready(function() { var map; var elevator; var myOptions = { zoom: 1, center: new google.maps.LatLng(0, 0), mapTypeId: 'terrain' }; map = new google.maps.Map($('#map_canvas')[0], myOptions); var addresses = ['Norway', 'Africa', 'Asia', 'North America', 'South America']; for (var x = 0; x < addresses.length; x++) { $.getJSON('http://maps.googleapis.com/maps/api/geocode/json?address=' + addresses[x] + '&sensor=false', null, function(data) { var p = data.results[0].geometry.location var latlng = new google.maps.LatLng(p.lat, p.lng); new google.maps.Marker({ position: latlng, map: map }); }); } }); }); //]]>
<script type="text/javascript" src="//code.jquery.com/jquery-1.9.1.js"></script> <script type="text/javascript" src="http://maps.google.com/maps/api/js?sensor=false&.js"></script> <style type="text/css"> #map_canvas { width: 500px; height: 500px; } </style> <div id="map_canvas"></div>
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.