如何使用ajax调用另一个php文件中的一个函数

Question

<script>    

        $(document).ready(function(){
        $("#amount").on('click', function(){
            var amount = this.value;
            $.ajax({
            url: "ipg-util.php/createHash",
             type: 'post',
              data: { "amount": amount
             },
                 success: function(response) { console.log(response); }
                });     

        });

    });
</script>

Answer 1

You can simply pass the Method to Call as part of the data property like so:

<script>    
    $(document).ready(function(){
    $("#amount").on('click', function(){
        var amount = this.value;
        $.ajax({
            url: "ipg-util.php",
            type: 'post',
            data: { "amount": amount, "callable": "createHash"},
        success: function(response) { console.log(response); }
        });     
    });
});
</script>

Then inside ipg-util.php You can do something like this:

    <?php
        $callable = isset($_POST['callable']) ? $_POST['callable'] : "default";
        $amount   = isset($_POST['amount'])   ? $_POST['amount']   : null;

        switch($callable){
            case "createHash":
                $response = createHash(); // CALL createHash METHOD DEFINED HEREIN
                break;
            case "doAnotherThing":
                $response = doAnotherThing(); // CALL doAnotherThing METHOD DEFINED HEREIN
                break;
            default:
                $response = default(); // CALL default METHOD DEFINED HEREIN
                break;

        }

        die(json_encode($response));

        function createHash(){

        }


        function doAnotherThing(){

        }


        function default(){

        }

Answer 2

$.ajax to call a server context or URL, whatever to invoke a particular 'action'. What you want is something like and the below code as follows:

$.ajax({ url: '/demo/websitepage',
         data: {action: 'calltofunction'},
         type: 'POST',
         success: function(output) {
                  alert(output);
                  }
});

On the server side, the action POST parameter should be read and the corresponding value should point to the method to invoke and the below code is used for doing that:

if(isset($_POST['action']) && !empty($_POST['action'])) {
    $action = $_POST['action'];
    switch($action) {
        case 'calltofunction' : test();break;
        case 'blah' : blah();break;
        // ...etc...
    }
}

Hope so this will be a better reference for this: https://en.wikipedia.org/wiki/Command_pattern