[英]Find and replace in an ajax call?
I have an ajax method that returns HTML. 我有一个返回HTML的ajax方法。
In that returned HTML I wish to replace certain divs with data. 在返回的HTML中,我希望用数据替换某些div。
I've looked at replaceWith but this seems to operate on dom objects only, not on HTML returned from an ajax call. 我已经看过replaceWith,但这似乎只对dom对象起作用,而不对从ajax调用返回的HTML起作用。
How can I replace certain divs inside the success method in an ajax call? 如何在ajax调用中替换成功方法内的某些div?
$.ajax({
url: '/get-data',
dataType: 'html',
success: function(html) {
//find div with class .test and replace it with <div class"abc"></div>
You can use replaceWith()
, like this: 您可以使用replaceWith()
,如下所示:
$.ajax({
url: '/get-data',
dataType: 'html',
success: function(html) {
var $html = $(html);
$html.find('.test').replaceWith('<div class="abc"></div>');
// work with $html as required here...
}
});
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