[英]having trouble converting my fetchedresultscontroller var to swift 3
I'm trying to convert this to swift 3我正在尝试将其转换为 swift 3
lazy var fetchedResultsControler: NSFetchedResultsController = {
let fetchRequest = NSFetchRequest(entityName: "Mesages")
fetchRequest.sortDescriptors = [NSSortDescriptor(key: "timestamp", ascending: true)]
fetchRequest.predicate = NSPredicate(format: "user.id = %@", self.friend!.id!)
let moc = (UIApplication.shared.delegate as! AppDelegate).managedObjectContext
let frc = NSFetchedResultsController(fetchRequest: fetchRequest, managedObjectContext: moc, sectionNameKeyPath: nil, cacheName: nil)
frc.delegate = self
return frc
}()
but it converts it to this :但它将其转换为:
lazy var fetchedResultsControler: NSFetchedResultsController = { () -> <<error type>> in
let fetchRequest = NSFetchRequest(entityName: "Mesages")
fetchRequest.sortDescriptors = [NSSortDescriptor(key: "timestamp", ascending: true)]
fetchRequest.predicate = NSPredicate(format: "user.id = %@", self.friend!.id!)
let moc = (UIApplication.shared.delegate as! AppDelegate).managedObjectContext
let frc = NSFetchedResultsController(fetchRequest: fetchRequest, managedObjectContext: moc, sectionNameKeyPath: nil, cacheName: nil)
frc.delegate = self
return frc
}()
and it gives me errors to put semi colons in random places, how do you declare something like this in swift 3将分号放在随机位置会给我带来错误,你如何在 swift 3 中声明这样的东西
you need to specify ResultType
您需要指定ResultType
lazy var fetchedResultsControler: NSFetchedResultsController<NSFetchRequestResult> = {
let fetchRequest = NSFetchRequest<NSFetchRequestResult>(entityName: "Mesages")
fetchRequest.sortDescriptors = [NSSortDescriptor(key: "timestamp", ascending: true)]
fetchRequest.predicate = NSPredicate(format: "user.id = %@", self.friend!.id!)
let moc = (UIApplication.shared.delegate as! AppDelegate).managedObjectContext
let frc = NSFetchedResultsController(fetchRequest: fetchRequest, managedObjectContext: moc, sectionNameKeyPath: nil, cacheName: nil)
frc.delegate = self
return frc
}()
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.