从CSV文件导出文件名列表并使用python复制到另一个目录

Question

i have one csv file that include the list of file: nome Desert Hydrangeas Jellyfish Koala Lighthouse Penguins Tulips I would like to create one script with python for copy this list of file from one directory to another directory, i can do this :

import csv
import os
import shutil
source = os.listdir("C:\Test")
destination = "C:\Test1"
with open('semplice1.csv') as csvfile:
       reader = csv.DictReader(csvfile)
       for row in reader:
           print(row['nome'])

in this wway i can print the name of the file. Can you help me to complete the code for copy only the list file? Thanks. enter code here

Answer 1

The issue is that os.listdir() returns a list of files contained in the directory that you give it - in this case "C:\\test".

Later on, when you then try and concatenate source with the individual files, you are therefor attempting to combine a list with a str. This is why you are getting the TypeError .

If all of the files are contained directly in "C:\\test", then you can drop the os.listdir() and do:

import csv
import os
import shutil

source = "C:\Test"
destination = "C:\Test1"

with open('semplice1.csv') as csvfile:
       reader = csv.DictReader(csvfile)
       for row in reader:
           print(row['nome'])
           a = row['nome']
           shutil.copyfile(os.path.join(source, a), destination)

Note the use of os.path.join() also as a better solution for building filepaths up.

Answer 2

I resolve my problem with this code:

import csv
import os
import shutil

source = "C:\Test"
destination = "C:\Test1"

with open('semplice1.csv') as csvfile:
       reader = csv.DictReader(csvfile)
       for row in reader:
           print(row['nome'])
           shutil.copyfile(os.path.join(source, row['nome']), os.path.join(destination, row['nome']))