如何在 Python 中的元组列表中对每个元组中的第一个值求和？

Question

I have a list of tuples (always pairs) like this:

[(0, 1), (2, 3), (5, 7), (2, 1)]

I'd like to find the sum of the first items in each pair, ie:

0 + 2 + 5 + 2

How can I do this in Python? At the moment I'm iterating through the list:

sum = 0
for pair in list_of_pairs:
   sum += pair[0]

I have a feeling there must be a more Pythonic way.

Answer 1

A version compatible with Python 2.3 is

sum([pair[0] for pair in list_of_pairs])

or in recent versions of Python, see this answer or this one .

Answer 2

sum(i for i, j in list_of_pairs)

也会做。

Answer 3

I recommend:

sum(i for i, _ in list_of_pairs)

Note :

Using the variable _ (or __ to avoid confliction with the alias of gettext ) instead of j has at least two benefits:

1. _ (which stands for placeholder) has better readability
2. pylint won't complain: "Unused variable 'j'"

Answer 4

If you have a very large list or a generator that produces a large number of pairs you might want to use a generator based approach. For fun I use itemgetter() and imap() , too. A simple generator based approach might be enough, though.

import operator
import itertools

idx0 = operator.itemgetter(0)
list_of_pairs = [(0, 1), (2, 3), (5, 7), (2, 1)]
sum(itertools.imap(idx0, list_of_pairs))

Note that itertools.imap() is available in Python >= 2.3. So you can use a generator based approach there, too.

Answer 5

Obscure (but fun) answer:

>>> sum(zip(*list_of_pairs)[0])
9

Or when zip's are iterables only this should work:

>>> sum(zip(*list_of_pairs).__next__())
9

Answer 6

Below is sample code, you can also specify the list range.

def test_lst_sum():
    lst = [1, 3, 5]
    print sum(lst)  # 9
    print sum(lst[1:])  # 8

    print sum(lst[5:])  # 0  out of range so return 0
    print sum(lst[5:-1])  # 0

    print sum(lst[1: -1])  # 3

    lst_tp = [('33', 1), ('88', 2), ('22', 3), ('44', 4)]
    print sum(x[1] for x in lst_tp[1:])  # 9

Answer 7

如果你不介意将其转换为numpy的数组，你可以使用np.sum在axis=0给出这里

Answer 8

                s,p=0,0
                for i in l:
                  s=s+i[0]
                  p=p+i[1]
               print(tuple(s,p))

1. enter code here