Java 8 数组列表。 哪个更快？ 在索引 0 处插入一项或使用一项创建新列表并将所有添加到新列表？

Question

Lets assume I call a third party API and get back a mutable N-many list of objects. This list could be as small as 10 objects or as large as a few thousand. I then always want to insert just one object at index 0 of that returned List. I know i can easily call add at index 0 but this is going to be O(n) as it shifts every object for the insert. My question is, would it be faster on average (processing wise) to create a new List with the item i plan on inserting at the beginning and then call addAll on that new List passing in the returned 3rd party N-many List?

Answer 1

It depends on the list implementation. If you truly have no visibility of what list implementation your third-party has given you, all you can do is empirical testing and benchmarking.

More likely, they're returning you one of the standard Java list types, and indeed you've tagged your question arraylist -- is that what you're given?

ArrayList.add(index,element) uses System.arrayCopy() to copy each shifted element from index n to n+1 , then writes the new element to its slot. That's O(n), however it's likely to be very fast indeed, since it will use the highly optimised system memmove routine to move whole chunks of RAM at a time. (see Why are memcpy() and memmove() faster than pointer increments? ).

In addition, if your extra element nudges the size of the list past the size of the allocated backing array, Java will create a new array and arraycopy the whole lot into there.

Bear in mind that you're only copying object references, not whole objects, so for 1000 elements, you're copying (worst case on a 64 bit machine) 64 bits * 1000 == 8 kilobytes of RAM.

Still, for really huge lists, the time it takes might become significant. Inserting into a linked list is cheaper (should be O(1) at the start or end)

You can make it an O(1) operation on an arbitrary List implementation by writing/finding a List implementation that is just a wrapper around the existing list. For example:

public class HeadedList<T> extends AbstractList<T> {

    private final List tail;

    public HeadedList(T head, List tail) {
       this.head = head;
       this.tail = tail;
    }

    public T get(int index) {
        return index == 0 ? head : tail.get(index - 1);
    }

    public int size() {
        return tail.size() + 1;
    }
}

(NB if you work in languages like Lisp/Clojure/etc you get very used to thinking of lists in this way)

But, only bother with this if benchmarking reveals that real performance problems are being caused by list building.

Answer 2

If the returned List impl is ArrayList, both options are the same: O(n).
If the returned impl is LinkedList, inserting at head is O(1).

There is an always O(1) option: Create a List wrapper class that is backed by the returned list but allows insertion at head by storing the inserted element internally. You would have to create a custom iterator to iterate over the inserted elemdnt then delegate to the list. Most methods would need similar customisation.

If it's only a 1000 or so elements I wouldn't bother, unless your application is complete and you've determined there is a measurable and severe enough performance problem at this operation.

If you were inserting multiple elements at head, then you would take a hit once to create a LinkedList, then each insertion would be O(1), but since you only have 1 to insert, don't bother.

KISS: Just insert the element into the returned list. I'm sure it will be faster enough, and most likely way faster than the library anyway.