如何修复返回未定义的代码？

Question

I have this code:

const liked_users = promises[1];
    const disliked_users = promises[0];
    if (liked_users.length > 0 || disliked_users.length > 0){
      for(var i = 0; i < liked_users.length; i++){
        for(var j = 0; j < disliked_users.length; j++){
          for(var k = 0; k < _USERS.length; k++){
            if(_USERS[k].useruid == liked_users[i].likedUseruid || disliked_users[j].dislikedUseruid){
              _USERS.splice(i, 1);
              i--;
              break;
            }

basically what is happening is that I access the firebase database and I pull out some data from my objects.

The problem comes where sometimes liked_users is going to be blank and therefore liked_users[i].likedUseruid will return undefined. When they are defined, the code runs fine.

How can I put in some conditional or block of code that allows it to be read in a way that accepts it can be undefined or doesn't run the code until it is defined? I can show more code if it will help.

Answer 1

In JavaScript if you put just variable name in if condition then it will check its available or not.

For example put this block

if(_USERS[k].useruid == liked_users[i].likedUseruid || disliked_users[j].dislikedUseruid){
....
}

in this

if(_USERS[k].useruid && liked_users[i].likedUseruid &&  disliked_users[j].dislikedUseruid){
....
}

The above condition will check that _USERS[k].useruid is available or not and will continue...

You can make condition as per your need.

I hope this will help you.