[英]Insert results from query into the same table
(For WordPress folks: I am creating a set of new "custom field"s called sidebar_buy_now by combining pairs of existing "custom field"s.) (对于WordPress人士:通过合并成对的现有“自定义字段”,我正在创建一组称为“ sidebar_buy_now”的新“自定义字段”。)
I have a table: wp_postmeta
with 4 fields: meta_id
, post_id
, meta_key
, meta_value
. 我有一张桌子: wp_postmeta
有4个字段: meta_id
, post_id
, meta_key
, meta_value
。
meta_id
is the primary key and should auto-increment. meta_id
是主键,应自动递增。
I have a working SELECT query which produces the desired result for the last 3 fields: post_id
, meta_key
, meta_value
: 我有一个有效的SELECT查询,该查询为最后3个字段产生所需的结果: post_id
, meta_key
, meta_value
:
SELECT L.`post_id`, "sidebar_buy_now" AS "meta_key",
CONCAT(L.`meta_value`, ' | ',R.`meta_value`)
AS "meta_value" FROM `wp_postmeta` L INNER JOIN `wp_postmeta` R
ON L.`post_id` = R.`post_id`
AND L.`meta_key` = 'sidebar_buy_now_url'
WHERE R.`meta_key` = 'sidebar_buy_now_title'
I want to insert the results of this query into the wp_postmeta
table while auto-incrementing meta_id
. 我想在自动递增meta_id
同时将此查询的结果插入wp_postmeta
表中。
This is the INSERT query I am trying which does not work: 这是我正在尝试的INSERT查询,不起作用:
INSERT into `wp_postmeta` (`post_id`,`meta_key`,`meta_value`)
SELECT L.`post_id`, "sidebar_buy_now" AS "meta_key",
CONCAT(L.`meta_value`, ' | ',R.`meta_value`) AS "meta_value" FROM `wp_postmeta` L INNER JOIN `wp_postmeta` R ON L.`post_id` = R.`post_id`
AND L.`meta_key` = 'sidebar_buy_now_url' WHERE R.`meta_key` = sidebar_buy_now_title'
Getting this error: 收到此错误:
#1136 - Column count doesn't match value count at row 1
. #1136 - Column count doesn't match value count at row 1
。
Perhaps because I don't know how to specify an auto-incrementing meta-id in the SELECT... (?) Anyone know how to fix this? 也许因为我不知道如何在SELECT ...(?)中指定自动递增的meta-id?有人知道如何解决此问题吗?
INSERT into wp_postmeta (post_id,meta_key,meta_value)
SELECT
L.post_id
,"sidebar_buy_now" AS "meta_key"
,CONCAT(L.meta_value, ' | ',R.meta_value) AS "meta_value"
FROM
wp_postmeta L
INNER JOIN wp_postmeta R
ON L.post_id = R.post_id AND L.meta_key = 'sidebar_buy_now_url'
WHERE R.meta_key = 'sidebar_buy_now_title'
Because meta_id is an auto increment column you don't actually insert anything into you. 因为meta_id是一个自动增量列,所以您实际上没有在其中插入任何内容。 You simply omit it from the insert statement. 您只需在插入语句中将其忽略即可。
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