c scanf整数与连续输入，但只需要读取一个

Question

I got input like 12345679890 but I just want to read 1 integer at a time, that is read 1 then 2 then 3 ... and do some operations next. However when I use scanf, it read all the numbers ie 1234567890. Can anyone help? Thank you!!

This is the code that I have

#include <stdio.h>

int main() {
    int input;
    scanf("%x",&input);

   while (scanf("%x",&input)==1){}
}

Answer 1

12345679890 is an integer, what you want to do is read one digit at a time. To do this, you would use the format string %1u rather than %x .

For a start, %x specifies a hexadecimal item, meaning it will accept a through f as well, and %d would allow for a leading sign which you probably don't want.

In addition, you appear to consume (and throw away) the first digit before you enter the loop, so you would be better off with something like:

#include <stdio.h>

int main(void) {
    unsigned int digit;
    while (scanf("%1d", &digit) == 1) {
        //doSomethingWith(digit);
    }
    return 0;
}