[英]javascript: How to convert dates entered in text fields to Date Format in Javascript
I have 2 text fields txtDateFrom
and txtDateTo
.我有 2 个文本字段
txtDateFrom
和txtDateTo
。 How can I convert the values from these fields to Date format, so I can calculate the number of days between DateFrom and DateTo?如何将这些字段中的值转换为日期格式,以便计算 DateFrom 和 DateTo 之间的天数?
I'm using the datepicker and when dates are selected they are in the mm\\dd\\yyyy
format我正在使用datepicker,选择日期时,它们处于
mm\\dd\\yyyy
格式
This is my function:这是我的功能:
function ValidateDateDiff(sender, args) {
var dateFrom = $('#cphBody_ExcessAuth_txtDateFrom').val();
var dateTo = $('#cphBody_ExcessAuth_txtDateTo').val();
var dateDiff = dateFrom - dateTo;
}
you could using jqueryUI.你可以使用 jqueryUI。
$("#datepicker").datepicker.parseDate( "mm\dd\yyyy", "09\20\2016" );
See this page for details: http://api.jqueryui.com/datepicker/有关详细信息,请参阅此页面: http : //api.jqueryui.com/datepicker/
Since you're not answering questions I just guessed..既然你不回答问题,我只是猜测..
var date = "03/15/1997";
var parts = date.split("/");
var date = new Date(parts[2]-1, parts[1], parts[0]);
alert(date.toLocaleFormat());
Demo: https://jsfiddle.net/e6mp0cgy/演示: https : //jsfiddle.net/e6mp0cgy/
As noted in the comments if you're using jQuery you can get the date object directly from jQuery.如评论中所述,如果您使用 jQuery,则可以直接从 jQuery 获取日期对象。 Otherwise check out the docs for more info.
否则,请查看文档以获取更多信息。
function ValidateDateDiff(sender, args) {
/*
var dateFrom = $('#cphBody_ExcessAuth_txtDateFrom').val();
var dateTo = $('#cphBody_ExcessAuth_txtDateTo').val();
*/
// for test
var dateFrom = "01\\01\\2016"; // date in format mm\dd\yyyy
var dateTo = "01\\05\\2016"; // date in format mm\dd\yyyy
var dateFromSplit = dateFrom.split("\\");
var dateToSplit = dateTo.split("\\");
var dateFromDate = new Date(dateFromSplit[2]+"-"+dateFromSplit[0]+"-"+dateFromSplit[1]);
var dateToDate = new Date(dateToSplit[2]+"-"+dateToSplit[0]+"-"+dateToSplit[1]);
var timeDiff = Math.abs(dateToDate.getTime() - dateFromDate.getTime());
var daysDiff = Math.ceil(timeDiff / (1000 * 3600 * 24)); // days difference
return daysDiff;
}
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