[英]More succinct initialization for SQLAlchemy instance
It's my first attempt at sqlalchemy. 这是我第一次尝试sqlalchemy。 I have a json file with my usr information and I would like to put them in a sqlite3 database file.
我有一个包含我的usr信息的json文件,我想将它们放在sqlite3数据库文件中。 It works but I find the instance initialization verbose since there are many columns in the table, as you can see below.
它可以工作,但是我发现实例初始化很冗长,因为表中有很多列,如下所示。
Is it possible to use a dictionary as input to initialize User()
? 可以使用字典作为输入来初始化
User()
吗? Something like a = User(usr)
? 类似于
a = User(usr)
吗?
import json
from sqlalchemy import *
from sqlalchemy.ext.declarative import declarative_base
engine = create_engine('sqlite:///tutorial.db', echo=True)
Base = declarative_base()
class User(Base):
__tablename__ = 'users'
id = Column(Integer, primary_key=True)
bbs_id = Column(String)
name = Column(String)
sex = Column(String, nullable=False)
city = Column(String)
state = Column(String)
class_type = Column(String, nullable=False)
class_id = Column(String, nullable=False)
latitude = Column(Float)
longitude = Column(Float)
def __repr__(self):
return "<User(bbs_id='%s', name='%s'>" % (self.bbs_id, self.name)
Base.metadata.create_all(engine)
with open('mydata.json') as fin:
usrs = json.load(fin)
usr = usrs[0]
a = User(id=usr['id'], bbs_id=usr['bbs_id'], name=usr['name'])
If you know the property names in the JSON object match the column names of the Python model, you can just change: 如果您知道JSON对象中的属性名称与Python模型的列名称匹配,则可以更改:
a = User(id=usr['id'], bbs_id=usr['bbs_id'], name=usr['name'])
to: 至:
a = User(**usr)
Double-star/ dict
unpacking passes each key/value pair of the dict
as if it were an argument being passed by keyword. 双星/
dict
拆包经过每个键/值对的的dict
就好像它是由关键字被传递的参数。 Since you didn't override __init__
for your model, it already allows and expects the arguments to be optional and passed by keyword, so this lines up perfectly. 由于您没有为模型覆盖
__init__
,因此它已经允许并且期望参数是可选的并通过关键字传递,因此这很完美。
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