比较两个对象数组，只得到数组的不同属性

Question

Array1 = { "Name": "Max", "Occupation": "Agri", "Location": "KGP" }; 

Array2 = { "Name": "Alex", "Occupation": "S.E", "Location": "KGP" }; 

In the above given 2 arrays i have different values in properties Name and Occupation but the location have the same value as that of Array1,

i want to compare the two arrays and get only the Different Property(Name and Occupation) of Array1

Answer 1

You could iterate over the keys of object1 and check the difference with the properties of object2 . If unequal, assign the value to the property of the result object3 .

 var object1 = { "Name": "Max", "Occupation": "Agri", "Location": "KGP" }, object2 = { "Name": "Alex", "Occupation": "SE", "Location": "KGP" }, object3 = {}; Object.keys(object1).forEach(function (k) { if (object1[k] !== object2[k]) { object3[k] = object1[k]; } }); console.log(object3);

Answer 2

var obj1 = { "Name": "Max", "Occupation": "Agri", "Location": "KGP" }; 

var obj2 = { "Name": "Alex", "Occupation": "S.E", "Location": "KGP" }; 

function getDifference(obj1,obj2){
  var diff = [];
  Object.keys(obj1).forEach(function(key){
  if (obj1[key] !== obj2[key]) diff.push(key);
  });
  return diff;
}
console.log(getDifference(obj1,obj2));

Answer 3

Your Array1 and Array2 are JavaScript Object . With 2 objects, you can perform this working, but dirty comparison. As soon as you will have more properties ... This will be a mess.

   var result = {};

    if (Array1.Name !== Array2.Name)
       result.Name = Array1.Name;
    if (Array1.Occupation !== Array2.Occupation)
       result.Occupation = Array1.Occupation.

   return result;

Arrays in JavaScript are declared with the following syntax:

var Array1 = [];

If you want an array of objects, you can write:

var Array1 = [ { "Name": "Max", "Occupation": "Agri", "Location": "KGP" }, { b"Name": "Max", "Occupation": "Agri", "Location": "KGP"} ]

But I doubt this is your intention there.

Answer 4

If the objective is to get mismatching keys, you can try something like this:

 function getMismatchKeys(o1,o2){ return Object.keys(o1).filter(function(k){ return o1.hasOwnProperty(k) && o2.hasOwnProperty(k) && o1[k] !== o2[k] }); } var obj1 = { "Name": "Max", "Occupation": "Agri", "Location": "KGP" }; var obj2 = { "Name": "Alex", "Occupation": "SE", "Location": "KGP" }; console.log(getMismatchKeys(obj1, obj2));

Answer 5

I will assume that Array1 and Array2 are meant to be json objects and not json arrays. I will also assume that you want a resulting object that is made up of only the key value pairs of Array1 which differ from Array2. Given those assumption you could use lodash omitBy to solve your problem.

 var Array1 = { "Name": "Max", "Occupation": "Agri", "Location": "KGP" }; var Array2 = { "Name": "Alex", "Occupation": "SE", "Location": "KGP" }; var result = _.omitBy(Array1, function(val, key){ return val === Array2[key];}); console.log('the key value pairs of Array1 that are different from Array2 are: ', result);

 <script src="https://cdn.jsdelivr.net/lodash/4.16.1/lodash.min.js"></script>