在文件中指定和操作列-Shell / bash

Question

line in file:

aaa, bbb, ccc, ddd, Sept 18, 2016 ##:##PM

trying to parse it out (desired output) -

aaa, bbb, ccc, ddd, "Sept 18, 2016 etc..."

using unix shell - trying to wrap last two columns in quotes for a date importing process. However, am trying to aim for a specified column approach in case a situation arises where the two columns are internal ie:

aaa, bbb, Sept 18, 2016 etc..., ccc, ddd

thus outputing:

aaa, bbb, "Sept 18, 2016 etc...", ccc, ddd

The command to display it is fine - as i can redirect it to a file and work with it from there

Answer 1

当将示例数据中的##:##替换为实际数字（并假设第二个“示例”中给出的“ etc ...”与第一个示例中的格式匹配）时，以下代码可用于GNU sed ：

sed -re 's@ ((Jan|Feb|Mar|Apr|May|June|July|Aug|Sept|Oct|Nov|Dec) [[:digit:]]+, [[:digit:]]{4} [[:digit:]]{1,2}:[[:digit:]]{2}[AP]M)([, ]|$)@ "\1"\3 @g'

Answer 2

Your unix tool for column manipulation is awk:

awk 'BEGIN{FS=", ";OFS=", "} {$5="\""$5; $6=$6"\""; print $0;}' YOUR_FILE.txt

$5 and $6 are the numbers of the columns you need to put " around. If you want to put " before the 5th and after the 7th column, just update the awk expression accordingly.