连接 - 从一个表中获取行然后获取另一个表中匹配的所有行？ 但不应重复第一个表匹配行

Question

I have two tables. Gallery and Joins.

Gallery
id | title
 1 | Dog Gallery
 2 | Cat Gallery

Joins
id | gallery_id | picture_id
 1 |      1     |     100
 2 |      1     |     101
 3 |      2     |     56
 4 |      1     |     102

I want to get id, gallery title from gallery - where id is equal to a specific id but also get all of the rows from joins where gallery id equals a specific gallery id.

So for above if the id was 1. I would want the dog gallery from gallery and picture_ids 100,101 and 102 from joins.

now the problem is that gallery title should comes one time. result is title=dog gallery picture_id=100,title=dog gallery picture_id=101,title=dog gallery picture_id=102 i need the result like this title=dog gallery picture_id=100,picture_id=101 and picture_id=102

Answer 1

You can use GROUP_CONCAT to have all the IDs as string

SELECT G.*, GROUP_CONCAT(DISTINCT P.picture_id ORDER BY P.picture_id DESC SEPARATOR ',') 
FROM gallery as G
LEFT JOIN pictures as P ON P.gallery_id = G.id 
GROUP BY G.id;