如何将参数传递给数组中的函数？

Question

So let's say I have an array of functions. How do I pass each function a value?

Here is a silly example:

var poopSong =[

function(this){ console.log('this is '+this);},
function(this){ console.log('that is '+this);},
function(this){ console.log('you are '+this);},

];

poopSong("poop")[1];

Answer 1

Just iterate through the array:

for(int i = 0; i < poopSong.Length; i++){
     poopSong[i]("poop"); //not poopSong("poop")[i];
}

Answer 2

poopSong is the array, so to get to an item, use an index. And since the items in the array are functions, execute a function with (), passing in a parameter ("value");

poopSong[1]("value");

Now if you want to got through each item, use a loop?

for(var i = 0; i < poopSong.length; i++)
{
    poopSong[i]("value");
}

or in the world of functional programing, use forEach

poopSong.forEach(function(item){ item("value"); });

is this what you are really after, cause its pretty basic stuff, or am I missing something.

Secondly, don;t use the word this as a parameter, its a reserved word and has a whole other context in JavaScript

Answer 3

First of all, you have to change the parameter you pass, this is a reserved keyword and I don't think you want to use it. Of course you can refer to this in the console.log() . However, I don't think that this is what your want. That being said the declartion of poopSong should be something like the following:

var poopSong = [
    function(a){ console.log('this is '+a);},
    function(b){ console.log('that is '+b);},
    function(c){ console.log('you are '+c);},
];

Then you can pass an argument to these functions as below:

poopSong[0]('you value');

We use the square brackets and an index to get an item of an array and since in our case the item is a function we can call it using parentheses and passing the corresonding arguments.

 var poopSong =[ function(a){ console.log('this is '+a); }, function(b){ console.log('that is '+b); }, function(c){ console.log('you are '+c); } ]; poopSong[0]("1"); poopSong[1]("2"); poopSong[2]("3");