简体   繁体   English

从 C# 获取 JSON 的值

[英]Get a value from JSON from c#

i am trying to get a value from a json file using c#.我正在尝试使用 c# 从 json 文件中获取值。 the json file looks more like the below string. json 文件看起来更像下面的字符串。

{
    "results": [
        {
            "address_components": [
                {
                    "long_name": "3",
                    "short_name": "3",
                    "types": [
                        "street_number"
                    ]
                }
            ],
            "formatted_address": "3, Puppalaguda - Manikonda Main Rd, Sri Laxmi Nagar Colony, Manikonda, Hyderabad, Telangana 500089, India",
            "geometry": {
                "bounds": {
                    "northeast": {
                        "lat": 17.4025788,
                        "lng": 78.3748307
                    },
                    "southwest": {
                        "lat": 17.4019665,
                        "lng": 78.3733937
                    }
                },
                "location": {
                    "lat": 17.4023166,
                    "lng": 78.37417409999999
                },
                "location_type": "RANGE_INTERPOLATED",
                "viewport": {
                    "northeast": {
                        "lat": 17.4036216302915,
                        "lng": 78.37546118029151
                    },
                    "southwest": {
                        "lat": 17.4009236697085,
                        "lng": 78.3727632197085
                    }
                }
            },
            "place_id": "EmkzLCBQdXBwYWxhZ3VkYSAtIE1hbmlrb25kYSBNYWluIFJkLCBTcmkgTGF4bWkgTmFnYXIgQ29sb255LCBNYW5pa29uZGEsIEh5ZGVyYWJhZCwgVGVsYW5nYW5hIDUwMDA4OSwgSW5kaWE",
            "types": [
                "street_address"
            ]
        }
    ]
}

I am looking for the formatted_address element from the json from C#.我正在从 C# 的 json 中寻找formatted_address元素。 I am getting lost in JObject, JArray, JToken.我在 JObject、JArray、JToken 中迷失了方向。 I am trying to use NewtonSoft JSON.我正在尝试使用 NewtonSoft JSON。 Thank you.谢谢你。

Using the LINQ-to-JSON API (JObjects) you can get the formatted address easily using the SelectToken method:使用LINQ-to-JSON API (JObjects),您可以使用SelectToken方法轻松获取格式化地址:

JObject obj = JObject.Parse(json);
string address = (string)obj.SelectToken("results[0].formatted_address");
Console.WriteLine(address);

Fiddle: https://dotnetfiddle.net/Fdvqkl小提琴: https : //dotnetfiddle.net/Fdvqkl

The easiest way would be to have model objects and then call最简单的方法是拥有模型对象,然后调用

var rootObject = JsonConvert.DeserializeObject(jsonString); 

With jsonString being your input.使用 jsonString 作为您的输入。 Then you can retrieve the formatted_address from the first array element like this like this:然后你可以像这样从第一个数组元素中检索 formatted_address :

var formattedAddress = rootObject.results[0].formatted_address;

Hope it helps.希望能帮助到你。

using Newtonsoft.Json nuget .使用Newtonsoft.Json nuget 。 and do something like that并做类似的事情

 static void Main(string[] args)
    {
        string json = "{'results':[{'SwiftCode':'','City':'','BankName':'Deutsche    Bank','Bankkey':'10020030','Bankcountry':'DE'},{'SwiftCode':'','City':'10891    Berlin','BankName':'Commerzbank Berlin (West)','Bankkey':'10040000','Bankcountry':'DE'}]}";

        var resultObjects = AllChildren(JObject.Parse(json))
            .First(c => c.Type == JTokenType.Array && c.Path.Contains("results"))
            .Children<JObject>();

        foreach (JObject result in resultObjects)
        {
            foreach (JProperty property in result.Properties())
            {
                // do something with the property belonging to result
            }
        }
    }

    // recursively yield all children of json
    private static IEnumerable<JToken> AllChildren(JToken json)
    {
        foreach (var c in json.Children())
        {
            yield return c;
            foreach (var cc in AllChildren(c))
            {
                yield return cc;
            }
        }
    }

change JTokenType.Array to whatever the type u wish , also change the "results" to the property name you wish to extractJTokenType.Array更改为您希望的任何类型,还将“结果”更改为您希望提取的属性名称

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM