使用 mysqli php 7 从数据库中检索图像

Question

I am trying to retrieve a png image file from the database

Here is the call from within the <img> tag inside body:

<img src="..\BankLogin\man.php?id=2" style="width:128px;height:150px">

Here's the man.php file:

<?php
   $link = mysqli_connect("localhost","root","","images");
   $imgId = $_GET['id'];
   if (!empty($imgId)) {
   $sqliCommand = "SELECT image FROM images WHERE id = $imgId";
   $result = mysqli_query($sqliCommand,$link);
   $row = mysqli_fetch_assoc($result);
   mysqli_close($link);   
   header("Content-type: image/png");
   echo $row['image'];
  }
?>

On running the code i just get an image frame with an 'unloaded image'(am i saying it correct?).I am pretty sure something is wrong in the man.php file, maybe in echo $row['image']. I am not sure how to go about making it right. Any help with this would be great.

Answer 1

If you want to retrieve the image which is stored as BLOB type in phpmyadmin you have to echo it as follows.

echo '<img src="data:image/jpeg;base64,'.base64_encode( $rows['image'] ).'"/>'

Example:

To Retrieve the BLOB image from the DB you have to do like this.

<?php
$db = mysqli_connect("localhost","root","","dbname"); //keep your db name
$query = "SELECT * FROM image WHERE id = $id";
$sth = $db->query($query);
$fetch=$sth->fetch_assoc();
echo '<img src="data:image/jpeg;base64,'.base64_encode( $fetch['image'] ).'"/>';
?>

For Inserting the image you need to follow the procedure like this So that if you encode it as base 64 you can retrieve the image perfectly without any error.

<?php
$conn = mysqli_connect("localhost","root","","DbName"); //keep your db name
$single_image = addslashes(file_get_contents($_FILES['images']['tmp_name']));
//U have to keep your DB table column name for insertion. I keep image type Blob.
$query = "INSERT INTO image (image) VALUES('".$single_image."')";  
$SQL = mysqli_query($conn, $query);
?>

Answer 2

The function mysqli_close should be called after the image data is echoed. This is because it destroys the result sets.

Also please fix the SQL Injection vulnerability:

$imgId = (int)$_GET['id'];