Javascript：如果内部标签为空，如何隐藏div

Question

I would like to hide the div with the class= "form-group" if the label inside doesn't have anything to display here is my html code:

echo'<div class="form-group">';
                        echo'<label for="exampleInputFile" class="tbh">'.$query2['req_1'].'</label>';
                        echo'<input type="file" name="my_image" accept="image/*" id="exampleInputFile"> ';
                        echo'</div>';

And my javascript is here:

<script type="text/javascript">
                        if($('label.tbh:empty')){
                            $('div.form-group').hide();
                        }
                        </script>

Is there any other way to do that? In my code it doesn't seem to work. Thanks in advance for the help.

Answer 1

Using .text() is a safer option. If the label is empty, .text() will return an empty string and negating it will give true . Refer to the interactive snippet with example below. I placed the relevant code in a button click handler to prove that it works after you click on it.

 $('button').click(function () { if (!$('.tbh').text()){ $('.form-group').hide(); } }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="form-group"> <label for="exampleInputFile" class="tbh"></label> <input type="file" name="my_image" accept="image/*" id="exampleInputFile"></div> <button>Click to hide</button> 

Answer 2

Try this:

if($('label.tbh').html() == ""){
     $('div.form-group').hide();
  }

Answer 3

You can do it like this:

/* Be sure that your dom is loaded */    
$( document ).ready(function() {
    /* Checking that the label is empty */
    if($("label").html().length == 0) {
        $('div.form-group').hide();   
    }
});

You can also use size() instead of length .

Answer 4

If you are using jQuery, you may do it by that way:

$("div.form-group label.tbh:empty").parent().hide();

It's a right way to do in inside document.ready callback:

$(document).ready(function(){
    $("div.form-group label.tbh:empty").parent().hide()
});

To include jQuery, add

echo '<script src="https://code.jquery.com/jquery-3.1.1.js"></script>';

to head of your script.

But it seems like you are using PHP or something like at your backend side? If so, you may do it on server-side code like this:

if(strlen($query2['req_1']) == 0)
{
    echo'<div class="form-group">';
    echo'<label for="exampleInputFile" class="tbh">'.$query2["req_1"].'</label>';
    echo'<input type="file" name="my_image" accept="image/*" id="exampleInputFile"> ';
    echo'</div>';
}

in this case you would not transfer unneeded data to the client.