我想使用php以默认输出格式执行此代码并输出？

Question

<?php 
$field_format = array('format'=>"date('Y-m-d',strtotime(created_date))");//array define here
echo 'default output '.date('Y-m-d',strtotime('26-09-2016'));
echo nl2br('<br/>');
echo nl2br('<br/>');
if (array_key_exists('format', $field_format)) {
    $value_in_format = $field_format['format'];
    $value_in_format = preg_replace('/created_date/','26-09-2016', $value_in_format);

// printed var_dump format

    var_dump(preg_replace('/created_date/','26-09-2016', $value_in_format));
    echo nl2br('<br/>');
    echo nl2br('<br/>');
    echo  $value_in_format; 

// i want this output should be same as default output

    echo nl2br('<br/>');
    echo nl2br('<br/>');
}
?>

Answer 1

I'm not sure what do you want to do, but your output is in another format because of the preg_replace..If you change your preg_replace with this line:

$value_in_format = preg_replace('/created_date/','2016-09-26', $value_in_format);

then your default output will be the same with the "$value_in_format" output.

Update:

<?php 
$field_format = array('format'=>"date('Y-m-d',strtotime(created_date))");//array define here
echo 'default output '.date('Y-m-d',strtotime('26-09-2016'));
echo nl2br('<br/>');
echo nl2br('<br/>');
if (array_key_exists('format', $field_format)) {
    $value_in_format = $field_format['format'];
    $value_in_format = preg_replace('/created_date/','"26-09-2016"', $value_in_format);
    //var_dump(preg_replace('/created_date/','\"26-09-2016\"', $value_in_format));
    echo nl2br('<br/>');
    echo nl2br('<br/>');
    eval("echo $value_in_format;");
    echo nl2br('<br/>');
    echo nl2br('<br/>');
}
?>