[英]Wrapping a line of preprocessor C++
How to wrap a line of preprocessor directive and ignore extra space? 如何包装一行预处理器指令并忽略额外的空间?
Test Code: 测试代码:
#error Line0\
Line 1
Result: 结果:
short_test.cpp(1): error: #error directive: Line0 Line 1
#error Line0\
^
While I want to keep the indent pattern in the test code, I don't want the spacing between line0 and line1 in the result. 虽然我想在测试代码中保留缩进模式,但我不希望结果中的line0和line1之间的间距。
Is that possible? 那可能吗?
Result that I want: 我想要的结果:
short_test.cpp(1): error: #error directive: Line0Line 1
no space between Line0 and Line1
Test Code that I want 我想要的测试代码
#error Line0\
(extra stuff?) Line 1 <-- keep the indent, ok to insert some extra stuff.
You can't, sorry. 你不能,抱歉。
The preprocessor will take precisely what you give it, including any indentation. 预处理器将精确地提供您提供的内容,包括任何缩进。
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