需要一个正则表达式来提取以特定字符结尾的字符串的前 7 或 8 个字符
[英]Need a regular expression that will extract first 7 or 8 characters of string that ends with specific characters
问题描述
First timer here and would greatly appreciate any assistance.
第一次来这里，将不胜感激任何帮助。 Need the regular expression to get the first 7 or 8 characters of variable length strings that end with abcd.com.需要正则表达式来获取以 abcd.com 结尾的变长字符串的前 7 或 8 个字符。 Example below:下面的例子：
tpbjm01-re0.abcd.com
xtsdjm01-re0.abcd.com
lnd2j902-re1.abcd.com
pqrjm02-re1.abcd.com
py3jm01-re1.uk.abcd.com
brhmjm02-re1.emea.abcd.com
rcnj902.abcd.com
cpzyjm01.abcd.com
So result should be:所以结果应该是：
tpbjm01
xtsdjm01
lnd2j902
pqrjm02
py3jm01
brhmjm02
rcnj902
cpzyjm01
Thank you in advance.先感谢您。
1 个解决方案
解决方案1
1 2016-09-27 15:55:54
You can use this regex:您可以使用此正则表达式：
^(\w{7,8})(?=.*abcd.com)
It will capture 7 or 8 char in the set [a-zA-Z0-9_] at the beginning它会在开始时捕获[a-zA-Z0-9_]集合中的 7 或 8 个字符
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