[英]Join two tables in one table using SQL
Good evening, 晚上好,
I have an issue trying to find a solution to join two tables : 我在尝试找到连接两个表的解决方案时遇到问题:
For example I have 例如我有
Table 1 : 表格1 :
Date | Item
12/03 | aaaa
12/03 | aaaa
14/03 | bbbb
14/03 | aaaa
15/03 | cccc
Table 2 : 表2:
Date | Item2
11/03 | aaaa
12/03 | aaaa
13/03 | bbbb
14/03 | aaaa
15/03 | cccc
I want to do a count to have this 我想算一下这个
Date | Count(Item1) | Count(Item2)
11/03 | 0 | 1
12/03 | 2 | 1
13/03 | 0 | 1
14/03 | 2 | 1
15/03 | 1 | 1
I have tried this so far, but it doesn't seems to work, it only give me the commun dates : 到目前为止,我已经尝试过了,但是似乎没有用,只是给了我一些公共日期:
SELECT F.DATE, COUNT(T1.Item1), COUNT(T2.Item2) FROM TABLE1
T1 LEFT JOIN TABLE2 T2 ON T1.date=T2.date
Date | Count(Item1) | Count(Item2)
12/03 | 2 | 1
14/03 | 2 | 1
15/03 | 1 | 1
Any help ? 有什么帮助吗?
Thanks 谢谢
In the below SQL, the first inline view is computing all the counts at date level and same applies with second query. By combining the results of left join and right join between these two inline views we can combine all the common and uncommon results from both tables as you described.
SELECT Date,
Item1,
Item2
FROM
(
SELECT T1.Date AS Date,
COUNT( T1.Item ) AS Item1,
COUNT( T2.Item ) AS Item2
FROM Table1 t1
LEFT JOIN
Table2 t2
ON t1.date = t2.date
GROUP BY t1.Date
UNION
SELECT T2.Date AS Date,
COUNT( T1.Item ) AS Item1,
COUNT( T2.Item ) AS Item2
FROM Table2 t2
LEFT JOIN
Table1 t1
ON t2.date = t1.date
GROUP BY t2.Date
) A
ORDER BY Date
;
SQL Fiddle Implementation :- SQL Fiddle实现:-
http://sqlfiddle.com/#!9/5b872/14 http://sqlfiddle.com/#!9/5b872/14
I think this is what you need - you group each table on the date using a count and then you add values from both grouped tables: 我认为这是您需要的-使用计数将日期中的每个表分组,然后从两个分组表中添加值:
DECLARE @tab1 TABLE
(
[Date] VARCHAR(5),
Item1 VARCHAR(100)
)
DECLARE @tab2 TABLE
(
[Date] VARCHAR(5),
Item2 VARCHAR(100)
)
INSERT INTO @tab1 ( Date, Item1 ) VALUES
('12/03','aaaa'),
('12/03','aaaa'),
('14/03','bbbb'),
('14/03','aaaa'),
('15/03','cccc')
INSERT INTO @tab2 ( Date, Item2 ) VALUES
('11/03','aaaa'),
('12/03','aaaa'),
('13/03','bbbb'),
('14/03','aaaa'),
('15/03','cccc')
;WITH grp AS (
SELECT [Date],COUNT(*) AS Item1, 0 AS Item2 FROM @tab1
GROUP BY [Date]
UNION
SELECT [Date],0, COUNT(*) FROM @tab2
GROUP BY [Date] )
SELECT grp.Date, SUM(grp.Item1) AS [CountItem1], SUM(grp.Item2) AS [CountItem2] FROM grp
GROUP BY grp.Date
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