[英]jquery validation condition prevent submit
how to create jquery for prevent form submit if status=1(from database) can't submit else can submit,where status i get from database.i'm so confused? 如何创建jQuery以防止表单提交,如果状态= 1(来自数据库)无法提交,其他人可以提交,我从数据库中获得的状态。我很困惑吗?
<form class="form-horizontal" id="myAnchor" method="post" action="<?php echo base_url(); ?>actrecord/add/<?php echo $data[0]->activity_id;?>">
<th><button onclick="warning()" type="submit" class="btn blue">new activity</button></th>
<script> document.getElementById("myAnchor").addEventListener("click", function(event){ event.preventDefault() }); </script> <script>function warning(){ alert("selesaikan dulu aktiiftas sebelumnya");} </script>
Add an onsubmit trigger in your form: 在您的表单中添加一个onsubmit触发器:
<form method='POST' action='blah' onsubmit='return check()'>
Then, in javascript with jquery: 然后,在带有jquery的javascript中:
<script>
function check()
{
$.ajax({
url:checkStatus.php,
success:function(data){
return (data==1)? false : true;
}
});
}
</script>
Just make sure checkStatus.php will echo the status from the db. 只要确保checkStatus.php将回显数据库的状态即可。
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